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2 years ago

An object completes 50 cycles in 150 s.

Physics

1 answer:

Lisa [10]2 years ago

3 0

Answer:

a. 3 seconds

b. 0.33 Hz

Explanation:

a. Period is defined by how long, in seconds, it takes for an object to complete one revolution, or cycle. If the object completes 50 cycles in 150 seconds, then it must complete one cycle every 150/50 = 3 seconds. Therefore, the period of the object is $\boxed{3\text{ seconds}}$ .

b. Frequency is given by $f=\frac{1}{T}$ where $T$ is the period, in seconds. Since we just found that the period is 3 seconds, plug in $T=3$ :

$f=\frac{1}{3}\approx \boxed{0.33\text{ Hz}}$

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3 years ago

You have a bowling ball with a mass of 4kg. You throw it with an acceleration of 10 m/s/s. With how much force will it hit the p

Eddi Din [679]

Answer:

<h3>The answer is 40 N</h3>

Explanation:

The force acting on an object can be found by using the formula

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mass = 4 kg

acceleration = 10 m/s²

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3 years ago

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2 years ago

URGENTTT PLEASE HELPPPP. You put m1 = 1 kg of ice cooled to -20°C into mass m2 = 1 kg of water at 2°C. Both are in a thermally i

STatiana [176]

Answer:

Explanation:

heat lost by water will be used to increase the temperature of ice

heat gained by ice

= mass x specific heat x rise in temperature

1 x 2090 x t

heat lost by water in cooling to 0° C

= mcΔt where m is mass of water , s is specific heat of water and Δt is fall in temperature .

= 1 x 2 x 4186

8372

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2 years ago

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of g

Morgarella [4.7K]

Here is the full question:

The rotational inertia I of any given body of mass M about any given axis is equal to the rotational inertia of an equivalent hoop about that axis, if the hoop has the same mass M and a radius k given by:

$k=\sqrt{\frac{I}{M} }$

The radius k of the equivalent hoop is called the radius of gyration of the given body. Using this formula, find the radius of gyration of (a) a cylinder of radius 1.20 m, (b) a thin spherical shell of radius 1.20 m, and (c) a solid sphere of radius 1.20 m, all rotating about their central axes.

Answer:

a) 0.85 m

b) 0.98 m

c) 0.76 m

Explanation:

Given that: the radius of gyration $k=\sqrt{\frac{I}{M} }$

So, moment of rotational inertia (I) of a cylinder about it axis = $\frac{MR^2}{2}$