Empirical formula of the compound is the simplest ratio of components making up the compound.
In 100 g there’s 87.1 g of Ag and 12.9 g of S.
Let’s calculate for 100 g of the compound
Ag S
Mass 87.1 g 12.9 g
Moles. 87.1 /107.8 g/mol 12.9/32 g/mol
=0.8 mol =0.4mol
Divide by the least number of moles
0.8/0.4 =2 0.4/0.4=1
Ratio of Ag to S is 2:1
Therefore empirical formula is Ag2S
The equation for calculating a mass is as follows:
m=n×M
Molar mass (M) we can determine from Ar that can read in a periodical table, and a number of moles we can calculate from the available date for N:
n(H2SO4)=N/NA
n(H2SO4)= 1.7×10²³ / 6 × 10²³
n(H2SO4)= 0.3 mole
Now we can calculate a mass of H2SO4:
m(H2SO4) = n×M = 0.3 × 98 = 27.8 g
It evaporates so the ice cube turns in to water then after words evaporat
- Due to the inability of the reaction to take place, the yield of 1-Bromobutane would drop.
- Since 1-Butanol won't react with the additional sodium bromide, bromination won't happen.
- If water had been supplied, the equilibrium would have shifted extremely far to the left, preventing the reactants from interacting with the acid and favoring the yield of 1-bromobutane instead.
<h3>What is Bromination?</h3>
- When a substance undergoes bromination, bromine is added to the compound as a result of the chemical reaction.
- After bromination, the result will have different properties from the initial reactant.
- For example, an alkene is brominated by electrophilic addition of .
- Benzene ring bromination by electrophilic aromatic substitution.
Learn more about Bromine here:
brainly.com/question/862562
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