All categories

3 years ago

Earth's axis is tilted. Tell what would happen if it was vertical instead.

Chemistry

2 answers:

slamgirl [31]3 years ago

7 0

I think the like term is 6 hope this is right

pshichka [43]3 years ago

6 0

Answer:

If earths axis is tilted, we would practically be in a night lock day and night. And the seasons would be different too

Explanation:

You might be interested in

URGENT!! I will have brainliest!!!

Vlad [161]

Answer:

sorry idk

Explanation:

3 0

3 years ago

There are two binary compounds of mercury and oxygen. heating either of them results in the decomposition of the compound, with

grandymaker [24]

$\text{Hg} \text{O}$ and $\text{Hg}_{2} \text{O}$ .

Assuming complete decomposition of both samples,

$m(\text{Hg}) = m(\text{residure})$
$m(\text{O}) = m(\text{loss})$

First compound:

$m(\text{O}) = m(\text{loss}) = 0.6498 - 0.6018 = 0.048 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.6018 \; g$

$n = m/M$ ; $0.6498 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.048 \; g / 16 \; g \cdot mol^{-1}= 0.003 \; mol$
$n(\text{Hg atoms}) = 0.6018 \; g / 200.58 \; g \cdot mol^{-1}= 0.003 \; mol$

Oxygen and mercury atoms seemingly exist in the first compound at a $1:1$ ratio; thus the empirical formula for this compound would be $\text{Hg} \text{O}$ where the subscript "1" is omitted.

Similarly, for the second compound

$m(\text{O}) = m(\text{loss}) = 0.016 \; g$
$m(\text{Hg}) = m(\text{residure}) = 0.4172 - 0.016 = 0.4012 \; g$

$n = m/M$ ; $0.4172 \; g$ of the first compound would contain

$n(\text{O atoms}) = 0.016 \; g / 16 \; g \cdot mol^{-1}= 0.001 \; mol$
$n(\text{Hg atoms}) = 0.4012 \; g / 200.58 \; g \cdot mol^{-1}= 0.002 \; mol$

$n(\text{Hg}) : n(\text{O}) \approx 2:1$ and therefore the empirical formula

$\text{Hg}_{2} \text{O}$ .

8 0

3 years ago

A certain skin lotion is a fine mixture of water and various oils. This lotion is cloudy and cannot be separated into oil and wa

nataly862011 [7]

Colloid

Explanation:

A lotion of this type is a typical colloid mixture.

A colloid is a homogeneous mixtures of two phases.
The dispersed phase and the dispersion medium.
Water is the dispersion medium and oil is the dispersed phase.

They have the following properties:

Liquid dispersed phase and liquid dispersion medium forms an emulsion and a lotion of this type is an example.
The particles are larger than those found in solutions.
The particles pass through ordinary filter paper.
They may be cloudy or clear .

learn more:

Heterogeneous mixtures brainly.com/question/1446244

#learnwithBrainly

4 0

3 years ago

The reaction is run at two temperatures where temperature 1 is lower than temperature 2. Which relationship is correct for eithe

Tasya [4]

Answer:

The answer is " $K_1 < K_2$ "

Explanation:

In the given question, the value of the $K=Ae^{-\frac{Ea}{RT}}$ and the $T_1$ is the rate value which is the constant that is $K_2>K_1$ . As per the temperature value when its increase rate is constantly increasing. $E_a$ is activation energy it is not dependent on the temperature that why the answer is $K_1 < K_2$ .

8 0

3 years ago

Earth is approximately 1.5 x 10^8 km from the sun the. How far is earth from the sun meters

Zielflug [23.3K]

Answer:

${ \tt{1 \: km = 1000m}} \\ { \tt{1.5 \times {10}^{8} km = (\frac{1.5 \times {10}^{8} \times 1000 }{1} )m}} \\ = 1.5 \times {10}^{11} \: metres$

4 0

3 years ago