Answer:
3. 63 in/s
Explanation:
The hawk was going 3 ells per second, that would be 21 palms per second since every ell is 7 palms its just multiplying 3 with 7. Now, since the hawk is going 3 ells per second, you multiply the 21 by 3 and get 63.
Answer:
Kb = 1.77x10⁻⁵
Explanation:
When NH₃, a weak base, is in equilibrium with waterm the reaction that occurs is:
NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)
And the dissociation constant, Kb, for this equilibrium is:
Kb = [NH₄⁺] [OH⁻] / [NH₃]
To find Kb you need to find the concentration of each species. The equilibrium concentrations are:
[NH₃] = 0.950M - X
[NH₄⁺] = X
[OH⁻] = X
<em>Where X is reaction coordinate.</em>
You can know [OH⁻] and, therefore, X, with pH of the solution, thus:
pH = -log [H⁺] = 11.612
[H⁺] = 2.4434x10⁻¹²
As 1x10⁻¹⁴ = [H⁺] [OH⁻]
1x10⁻¹⁴ / 2.4434x10⁻¹² = [OH⁻]
4.0926x10⁻³ = [OH⁻] = X
Replacing, concentrations of the species are:
[NH₃] = 0.950M - X
[NH₄⁺] = X
[OH⁻] = X
[NH₃] = 0.9459M
[NH₄⁺] = 4.0926x10⁻³M
[OH⁻] = 4.0926x10⁻³M
Replacing in Kb expression:
Kb = [NH₄⁺] [OH⁻] / [NH₃]
Kb = [4.0926x10⁻³M] [4.0926x10⁻³M] / [0.9459M]
<h3>Kb = 1.77x10⁻⁵</h3>
Answer:
3.09 atm
Explanation:
Given that:
Volume of container A = 717 mL
Pressure of container A = 2.80 atm
Volume of container B = 174 mL
Pressure of container B = 4.30 atm
Now, if the valve are being removed and the gases are allowed to mix together; then
The total final pressure can be calculated by using the formula:
I’m so sorry about the other guy! The answer is A. Infertile soil honey
God Bless!! <3
