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user100 [1]
3 years ago
14

Hi All,

Chemistry
1 answer:
Novosadov [1.4K]3 years ago
4 0

Answer:Combination.

Decomposition.

Single displacement.

Double displacement.

Combustion.

Redox.

Explanation:

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Refer to the experiment below:
saul85 [17]

Answer:

I think you are correct with your answer.

Explanation:

But I don't think that the explanation is correct because I think that it is the formation of both baking soda and water that makes it work...Vinegar doesn't make gas bubbles maybe because it hasn't reacted or maybe because it is not the right ingredient for the solution you are looking for. Thank you for the question.....Am not sure I really helped in your question but thank you..

8 0
2 years ago
What is the frequency of radiation whose wavelength is 0.73 nm?
Travka [436]
405 PHz
I might be wrong because that might be for 0.74 nm. We will see with out people answers
8 0
3 years ago
How do you determine the chemical reactivity for metals by using the periodic table?
vesna_86 [32]

Answer:

Chemical reactivity increases down a group and decreases from left to right of a period.

Explanation:

The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.

4 0
3 years ago
Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz
stiv31 [10]

Answer: Freezing point of a solution will be -1.16^0C

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

K_f = freezing point constant = 5.12^0C/m

m= molality

\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}

(5.50-T_f)^0C=6.68

T_f=-1.16^0C

Thus the freezing point of a solution will be -1.16^0C

3 0
3 years ago
Iodine-131 has a half-life of 8 days. If the amount of iodine-131 in the orginial sample is 8 g, how much iodine-131 will remain
hram777 [196]

1/32

Explanation it stated with half on 8 days then that means you divide 24 and 8 so its 3 and you have to multiply ✖ ½

7 0
3 years ago
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