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zvonat [6]
4 years ago
13

What other product occurs when ac-222 releases an alpha particle?

Chemistry
1 answer:
irga5000 [103]4 years ago
3 0
There is fr-218

hope this did the job, have a nice rest of your day!!

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How many grams of As2S3 are in 3.25 moles?
laiz [17]

Answer:

Explanation:

Molar mass of As2S3= {75(2) + 32(3)}

= 150 + 96 = 246g/mol

Amount = 3.25mole

And

Amount = mass/ molar mass

mass = amount × molar mass

Mass = 3.25 × 246

mass = 799.5g

6 0
4 years ago
Which factor can increase the potential energy of an object?
OLEGan [10]

Answer:

Increase in height from the ground.

Explanation:

Potential energy =mass×acceleration due to gravity×height.

P.E= mgh

4 0
3 years ago
A sample of rubidium contains two different isotopes. 72.15% of the sample
Leona [35]

Answer:

Average atomic mass  = 85.557 amu.

Explanation:

Given data:

Percent abundance of Rb-85 = 72.15%

Percent abundance of Rb-87 = 27.85%

Average atomic mass = ?

Solution:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass = (72.15×85)+(27.85×87) /100

Average atomic mass =  6132.75 + 2422.95 / 100

Average atomic mass = 8555.7 / 100

Average atomic mass  = 85.557 amu.

4 0
3 years ago
Please help me with this homework
Andru [333]

Answer:

dude

Explanation:

dude use a calculator, \ USE A CALCULATOR

6 0
3 years ago
A chemist dissolves 248mg of pure hydrochloric acid in enough water to make up 140mL of solution.Calculate the pH of the solutio
evablogger [386]

Answer : The pH of the solution is, 1.31

Explanation : Given,

Mass of HCl = 248 mg = 0.248 g      (1 mg = 0.001 g)

Volume of solution = 140 mL

Molar mass of HCl = 36.5 g/mole

First we have to calculate the concentration of hydrochloric acid.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }HCl\times 1000}{\text{Molar mass of }HCl\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{0.248g\times 1000}{36.5g/mole\times 140mL}=0.0485mole/L=0.0485M

The concentration of HCl is, 0.0485 M

As we know that, HCl dissociates to give hydrogen ion and chloride ion.

The dissociation reaction is:

HCl\rightarrow H^++Cl^-

Concentration of HCl = Concentration of H⁺ = Concentration of Cl⁻ = 0.0485 M

Now we have to calculate the pH of the solution.

pH : It is defined as the negative logarithm of hydrogen ion concentration.

Mathematically,

pH=-\log [H^+]

pH=-\log (0.0485)

pH=1.31

Therefore, the pH of the solution is, 1.31

6 0
3 years ago
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