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Oduvanchick [21]
3 years ago
6

Which statement best explains how electrons form a covalent bond in a molecule?

Chemistry
2 answers:
yKpoI14uk [10]3 years ago
5 0

Answer:

covalent bond, also called a molecular bond, is a chemical bond that involves the sharing of electron pairs between atoms

the sharing of electrons allows each atom to attain the equivalent of a full outer shell, corresponding to a stable electronic configuration.

Explanation:

Phantasy [73]3 years ago
3 0

Answer:

B. A pair of electrons belongs to two atoms at the same time

Explanation:

Covalent bonding occurs between two unstable elements through sharing of pair of electrons. During bonding, two elements combines and shares a pair of electron to form a molecule. This electron completes both elements outermost shell and thereby forming a compound. Example of a compound that forms covalent bonding is sodium chloride (NaCl).

Sodium which is a group1 element possesses just one electron in its outer shell while chlorine, a group 7 element possess 7 valence electrons in its outermost shell making them unstable. Sodium acts as a donor by donating its lone pair of electron to chlorine thereby becoming a positively charged element while chlorine accepts this line pair of electron to completes its outermost shell making it stable and becoming negatively charged particle (being the acceptor). This bonding between this atoms if different elements is what is called covalent bonding.

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The relative atomic mass of Chlorine is 35.45. Calculate the percentage abundance of the two isotopes of Chlorine, 35Cl and 37Cl
nata0808 [166]

Answer:

35Cl = 75.9 %

37Cl = 24.1 %

Explanation:

Step 1: Data given

The relative atomic mass of Chlorine = 35.45 amu

Mass of the isotopes:

35Cl = 34.96885269 amu

37Cl = 36.96590258 amu

Step 2: Calculate percentage abundance

35.45 = x*34.96885269 + y*36.96590258

x+y = 1  x = 1-y

35.45 = (1-y)*34.96885269 + y*36.96590258

35.45 = 34.96885269 - 34.96885269y +36.96590258y

0.48114731 = 1,99704989‬y

y = 0.241 = 24.1 %

35Cl = 34.96885269 amu = 75.9 %

37Cl = 36.96590258 amu = 24.1 %

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A. Describe the molecule chlorine dioxide, CIO in terms of three possible resonance structures.
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Answer:

See explanation

Explanation:

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The molecule has an odd number of valence electrons, hence, it is generally regarded as a paramagnetic radical. None of the proposed Lewis structures for the molecule is satisfactory because none of them obeys the octet rule.

From the images attached, one can easily see that the electron dots around the oxygen and chlorine atoms does not satisfy the octet rule in all the resonance structures shown.

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