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2 years ago

13

Problem page an item is regularly priced at $65 . it is on sale for 60% off the regular price. how much (in dollars) is discount

ed from the regular price?

1 answer:

Sauron [17]2 years ago

5 0

65(.4) = 26$

65- 26 = 39

The answer is $39

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6n+n+14=0 i need the math

Fofino [41]

Let's solve your equation step-by-step.<span><span><span><span>6n</span>+n</span>+14</span>=0</span>

Step 1: Simplify both sides of the equation.<span><span><span><span>6n</span>+n</span>+14</span>=0</span><span>Simplify: (Show steps)</span><span><span><span>7n</span>+14</span>=0</span>

Step 2: Subtract 14 from both sides.<span><span><span><span>7n</span>+14</span>−14</span>=<span>0−14</span></span><span><span>7n</span>=<span>−14</span></span>

Step 3: Divide both sides by 7.<span><span><span>7n</span>7</span>=<span><span>−14</span>7</span></span><span>n=<span>−2</span></span>

Answer:<span>n=<span>−<span>2</span></span></span>

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2 years ago

Help on geometry plzzzz find b

Nikitich [7]

Answer:

5.5 cm

Step-by-step explanation:

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2 years ago

Can someone help me with this question please?.

Taya2010 [7]

Answer: I think its n-12

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2 years ago

PLS ANSWER NOW WILL EARN BRAINLIEST IF RIGHT

velikii [3]

3.79+2.57+5.8=12.16

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2 years ago

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0

3 years ago