Answer:
tension in rope = 25.0 N
Explanation:
- Two forces act on the suspended weight. The force coming down is the gravitational force and the upward force by the tension in the rope.
- Since the suspended weight is not accelerating so that the net force will be zero. Therefore the tension in the rope should be 25 N.
∑F = F - W = 0
so
F = W
so tension in rope = F = T = 25 N
Answer:
When the source of pollution is widely distributive in nature, it is called as the Non-point source pollution, for example, <em>acid rain</em>.
Explanation:
the source of pollution when is <em>not concentrated over a particular area</em> or any particular defined pinpoint is termed to be as the Non - point source pollution.
this type of pollution is very hard to be monitored or controlled due to its nature of widely distributive nature of the origin. It has <em>several pathways</em> for the effect to undertake and thus the control over the effect is <em>not easily accessible. </em>
For example, during rain, the tree fall off can enter water stream from any source, either be it open lake or ponds or even street fall offs.
Answer: 5.5 m/s
Explanation:
As we are told the runner accelerates at a constant rate, we can use the following equation:
Where:
is the runner's final velocity
is the runner's initial velocity
is the runner's constant acceleration
is the time it takes the runner to reach the final velocity
Finally:
Answer:first of all what is your question and i can give and example which is Use them when you have 2 forces named Fa & FF or Fg & Ff acting in opposite directions on an object and you need to know the resultant of your 2 forces.
Explanation:
i searched it up
Answer:
v = 1.03 m / s
Explanation:
For this case we must use energy conservation. Let's define an energy system at the lowest point of the movement.
Initial energy lowest point
Em₀ = K = ½ m v²
Final energy highest point
= U = m g y
Energy is conserved
Em₀ =
½ m v² = m g y
v = √ (2g y)
Let's use trigonometry to find the height
cos 20 = L’/ L
L’= L cos 20
The height of the displacement is the total length minus L ’
y = L - L’
y = L - L cos 20
y = L (1- cos 20)
Let's replace
v = √ (2g L (1-cos 20))
Let's calculate
v =√(2 9.8 0.90 (1- cos 20))
v = 1.03 m / s