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salantis [7]
3 years ago
11

A 0.030-m3 container is initially evacuated. Then, 4.0 g of water is placed in the container, and, after some time, all the wate

r evaporates. If the temperature of the water vapor is 388 K, what is its pressure?
Physics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

23895.05 Pa

Explanation:

V = 0.03 m³

mass, m = 4 g

Temperature, T = 388 K

Let P be the pressure.

number of moles, n = 4 / 18 = 0.22

Use ideal gas equation

PV = n RT

P x 0.03 = 0.22 x 8.314 x 388

P = 23895.05 Pa

Thus, the pressure is 23895.05 Pa.

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Explanation:

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In a region of space where gravitational forces can be neglected, a sphere is accelerated by a uniform light beam of intensity 8
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Answer:

The correct answer is B

Explanation:

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To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface

       P = I / c        absorbent surface

       P = F / A

       F / A = I / c

       F = I A / c

The area of ​​area of ​​a circle is

      A = π r²

We replace

     F = I π r² / c

Let's calculate

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Density is

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      m = ρ V

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      m = 4500 (4/3 π (1 10⁻⁶)³)

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Let's calculate the acceleration

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