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Dmitrij [34]
3 years ago
8

The Rossi family ate 1/3 of a cheese pizza and 2/3 of a vegetarian pizza. How much total pizza did the Rossi family eat?

Mathematics
2 answers:
kipiarov [429]3 years ago
6 0
It would be one whole that will be your answer
kupik [55]3 years ago
3 0
1/3 plus 2/3 = 1 whole
So, the Rossi family ate 1 whole pizza
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Write an irrational number that can be added to the irrational number the square root of 15 to get a rational sum of 2
aniked [119]

Answer:

Step-by-step explanation:

if u is an irrational number added to a rational number (sqrt 15) to yield 2, then that would mean u would = root -1.78.....

which means you wouldn't have a real solution. if you want a complex answer, it would be sqrt(1.78)i

7 0
3 years ago
Help me with this question i tried multiple time to solution it always wrong
maw [93]
7/9-1/3 or 7/9-3/9= 4/9 is the answer
4 0
3 years ago
X+9^4=[4234+56/23] x94 = ?<br><br> pelase show work
Lana71 [14]

Answer:

391,660.6

Step-by-step explanation:

First we need to do what is in the parentheses. 56/23 equals 2.4. 4234 + 2.4 is 4236.4...  4236.4 times 94 is 398,221.6... Now 9 to the fourth power is 6561. x + 6561 is 398,221.6 so x equals 391,660.6... I hope this helps and please make me the brainliest. Thanks!

3 0
3 years ago
Can someone please help me with this questions
Ludmilka [50]

Step-by-step explanation:

a. 3⁴

b. 7⁵

c. 10²

d. 5⁷

Hope this helps?

8 0
3 years ago
Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number
sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

E(X)=\sum x\cdot P(X=x)

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner:   1           2           3          4           5              6

Amount earned (<em>X</em>):   $1        $4         $7        $10     -$8.75     -$8.75

Probability:                 1/6       1/6         1/6        1/6         1/6           1/6

Compute the expected value of <em>X</em> as follows:

E(X)=\sum x\cdot P(X=x)

         =(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})

         =\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}

         =\frac{1+4+7+10-8.75-8.75}{6}

         =0.75

Thus, the expected value of playing the game is $0.75.

5 0
3 years ago
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