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A laser is used in eye surgery to weld a detached retina back into place. The wavelength of the laser beam is 503 nm, while the

V125BC [204]

Answer:

Number of proton emmitted by laser= $2.48*10^17proton$

Explanation:

Energy is the ability to cause change; power is directly proportional to energy and its the rate energy is utilized.

Power=energy/time.

First we need to calculate the total energy used which is equal to the total power utilized.

E(total)= P( total) = 1.4W × 0.070 s = $0.098J$

CHECK THE ATTACHMENT FOR THE REMAINING DETAILED CALCULATION

4 0

4 years ago

A sample of Neon is in a sealed container held under isothermic conditions. The initial pressure and volume are 2.7 atm and 4.5

Marina CMI [18]

Answer:

The final volume in mL is 7.14 mL or 7.1 mL.

Explanation:

1.Use Boyle's Law( $P_{1} V_{1}= P_{2} V_{2}$ ). Re-arrange to solve for $V_{2}$ for the final volume.

2. Plug in values. $V_{2} =\frac{(2.7 atm)(4.5 mL)}{(1.7 atm)} = 7.14 mL$

3 0

2 years ago

Which of the following reactions will have the largest equilibrium constant (K) at 298 K? Which of the following reactions will

hram777 [196]

Answer:

2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ

Explanation:

If we know the ΔG° of a chemical reaction it is possible to calculate the equilibrium constant (k) of this procedure with the next equation:

ln Keq = -ΔG° / RT (1)

Where: Keq is equilibrium contant, ΔG° is standard state free energy change, R is gas constant and T is temperature.

Watching (1), it is possible to know that the large negative ΔG° the largest equilibrium constant. That is because R and T are always positive and to cancel the negative of equation it is necessary that ΔG° be negative.

Knowing this, is the oxidation of Hg the reaction that has the largely negative ΔG°. So, this reaction will have the largest equilibrium constant.

2 Hg(g) + O₂(g) → 2 HgO(s) ΔG° = -180.8 kJ

CaCO₃(s) → CaO(s) + CO₂(g) ΔG° =+131.1 kJ

3 O₂(g) → 2 O₃(g) ΔG° = +326 kJ

Fe₂O₃(s) + 3 CO(g) → 2 Fe(s) + 3 CO₂(g) ΔG° = -28.0 kJ

I hope it helps!

8 0

3 years ago

Sea-Floor Spreading1. The arrows on the figure show the ocean floor spreading from the ridge. What are three kinds of evidence s

AlexFokin [52]

Answer is

-B

Explanation

8 0

3 years ago

Allotropes are different molecular forms of an element, such as dioxygen (O₂) and ozone (O₃). (b) Calculate the ratio of densiti

kipiarov [429]

The ratio of densities, d₀₃/d₀ is 3:2

We know that at STP all gas have the same volume that is $22.4 \mathrm{~L}$ .

Dioxygen $1 \mathrm{mLe} \mathrm{O}_{2}=32 \mathrm{gm} / \mathrm{moL} .$

Ozone 1 mole $\mathrm{O}_{3}=48 \mathrm{gm} / \mathrm{mol}$ .

$\begin{aligned} \therefore \text { density of } \mathrm{O}_{2} \text { at STP } &=\frac{\text { mass of } \mathrm{O}_{2}}{\text { volume }} \\ \text { or, } d_{\mathrm{O}_{2}} &=\frac{32 \mathrm{gm} / \mathrm{mol}_{\mathrm{o}}}{22.4 \mathrm{~L}} \end{aligned}$

$\therefore$ The ratio of densities,

$\frac{d_{3}}{d o_{2}}=\frac{\frac{48 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}{\frac{32 \mathrm{gm} / \mathrm{mol}}{22.4 \mathrm{~L}}}$

$\frac{d 0_{3}}{d 0_{2}}=\frac{3}{2}$

do3: do2 = 3:2

Oxygen is found naturally as a molecule. two oxygen atoms strongly bind together with a covalent double bond to shape dioxygen or O2. Oxygen is normally observed as a molecule. it is referred to as dioxygen.

After hydrogen and helium, oxygen is the third most plentiful element in the universe and the most established element in the world. two atoms of the factors combine to generate dioxygen, an odourless and colourless diatomic gasoline with the formulation O2, at ordinary temperature and stress.

Learn more about dioxygen brainly.com/question/19905677

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4 0

2 years ago