Answer:
Explanation:
To determine what is been asked in this question, firstly, the formula to determine the number of atoms present in a substance must be used. The formula is
number of atoms = n × 6.02 × 10²³
where n is the number of moles
6.02 × 10²³ is avogadro's number
The number of atoms needed (to be present) has already been provided in the question as 2 × 10²⁴
Thus;
2 × 10²⁴ = n × 6.02 × 10²³
n = 2 × 10²⁴ ÷ 6.02 × 10²³
n = 3.32
The number of moles of carbon that will be placed in the reaction will be 3.32 but to determine the amount/mass of carbon that will be used in the reaction, we will use the formula
n = mass/molar mass
The molar mass of carbon is 12 g/mol
Thus;
3.32 = mass/12
mass = 3.32 × 12
mass = 39.84 g
The mass of carbon that will be required for the reaction will be 39.84, the procedure above shows how to obtain this amount.
Answer:
Just make it sound right please it don't even add up what was you even thinking like come on now...lol
Explanation:
What does this mean I don't understand your question.
Answer:
<u><em>i hope it work</em></u>
Explanation:
as
accurate reading range = reading ± uncertainty
so you have to say about accurate reading that its,lies in range
=(6389-436) →(6389+436)
=5953→6825
and the correct number of significant would be 3
Electromagnetic radiation is a form of energy that propagates as both electrical and magnetic waves traveling in packets of energy called photons. There is a spectrum of electromagnetic radiation with variable wavelengths and frequency, which in turn imparts different characteristics.
This means that electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space. ...
Hello!
First, we can assume the density of water to be
1 g/mL, so the volume of water would be
725 mL. The density of Acetic Acid (Pure) is
1,05 g/mL so 8 grams would represent
7,61 mLNow we can apply the following conversion factor to calculate the molarity of the solution, using the molar mass of Acetic Acid:
![[CH_3CO_2H]=\frac{8 g_{CH_3CO_2H} }{725 mL + 7,61 mL}* \frac{1000 mL}{1 L}* \frac{1 mol_{CH_3CO_2H} }{60,05 g_{CH_3CO_2H} }](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D%5Cfrac%7B8%20g_%7BCH_3CO_2H%7D%20%20%7D%7B725%20mL%20%2B%207%2C61%20mL%7D%2A%20%5Cfrac%7B1000%20mL%7D%7B1%20L%7D%2A%20%5Cfrac%7B1%20mol_%7BCH_3CO_2H%7D%20%7D%7B60%2C05%20g_%7BCH_3CO_2H%7D%20%7D)
![[CH_3CO_2H]=0,1818 M](https://tex.z-dn.net/?f=%5BCH_3CO_2H%5D%3D0%2C1818%20M)
So, the concentration of acetic acid would be
0,1818 MHave a nice day!
