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VMariaS [17]
3 years ago
13

What is the percent composition by mass of oxygen in ca(no3)2 (gram-formula mass = 164 g/mol)?a.9.8%b.29%c.48%d.59%?

Chemistry
2 answers:
Mila [183]3 years ago
8 0
Percent composition by mass of oxygen =
((16.0*6)/(40.1+2*(14.0+16.0*3)))*100%
= 58.5%
therefore, the answer is D
iris [78.8K]3 years ago
4 0

Answer:

A. 9.8%

Explanation:

Percentage Composition = (Mass of element /  Mass of compound) * 100

Mass of oxygen = 16g

Molar mass of Ca(NO3)2

Where;

Ca = 40

N = 14

O =16

Molar mass = 40 + 2[14 + 3(16)] = 164

Substituting into the formular;

Percentage composition = (16 / 164) * 100

Percentage Composition = 0.0975 * 100

Percentage Composition = 9.75% ≈ 9.8 %

Correct option = A

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2Fe(OH)3 Fe2O3+3H2O how many grams of Fe2O3 are produced if 10.7 grams of Fe (OH)3 react in this way
sasho [114]

Answer: 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

Explanation:

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)  

Putting values in equation 1, we get:

\text{Moles of} Fe(OH)_3=\frac{10.7g}{106.87g/mol}=0.100mol  

The chemical equation for the reaction is

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O

By Stoichiometry of the reaction:

2 moles of Fe(OH)_3 produce = 1 mole of Fe_2O_3

So, 0.100 moles of Fe(OH)_3 produce= \frac{1}{2}\times 0.100=0.05mol of Fe_2O_3  

Mass of Fe_2O_3 =moles\times {\text{Molar Mass}}=0.05mol\times 159.69g/mol=7.98g  

Hence 7.98 grams of Fe_2O_3 are produced if 10.7 grams of Fe(OH)_3 are reacted.

3 0
2 years ago
WILL GIVE BRAINLIEST!!!
NemiM [27]

1)Is =425·G

2) Is=54· g

6 0
3 years ago
A solution that has a large amount of dissolved solute is called
kvasek [131]

Answer: It is an unsaturated solution

Explanation: This is because it has more solute than a normal solution.

6 0
3 years ago
Which measure of a gas does the expression
Usimov [2.4K]

Answer:

A. volume

Explanation:

Generally the equation for the  ideal gas  is mathematically given as  

PV=nRT

Where  

P=pressure  

V=volume  

R=gas constant  

n=Number of Moles  

T=Temperature

 

Therefore  

V=nRT/P  

Option A

For more information on this visit

brainly.com/question/17756498

7 0
2 years ago
In the important industrial process for producing ammonia (the Haber Process), the overall reaction is:
Kisachek [45]

Answer:

Explanation:

Here we have to use stoichiometry.

First of all, we have to calculate the mass of 100% of yield:

1.7 g ------- 98%

X -------- 100%

X = 1.73 g (approximately)

Second, we have to calculate the mass of N2 that is necessary to react to produce the mass of 1.73g of NH3. To do that, we have to use the Molar mass of N2 and NH3 and don't forget the stoichiometric relationship between them.

Molar Mass N2 : 14x2 = 28 g/mol

Molar Mass NH3: 14 + 3 = 17 g/mol

28g (N2) ------- 17x2 (NH3)

X ------------ 1.73 g

X = 1.42 g (approximately)

5 0
3 years ago
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