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Elenna [48]
3 years ago
14

Why would advertising be more important in a magazine publishing than it is in a newspaper?

Computers and Technology
2 answers:
Bond [772]3 years ago
3 0
Newspapers are irrelevant now, magazines will get you much more viewers.
maks197457 [2]3 years ago
3 0

Answer:

newspaers are erelavent now magazines would get u much more views

Explanation:

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a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv
Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that  cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

<em>#include <bits/stdc++.h></em>

<em>using namespace std;</em>

<em>// chracter to digit mapping, and the inverse</em>

<em>// (if you want better performance: use array instead of unordered_map)</em>

<em>unordered_map<char, int> c2i;</em>

<em>unordered_map<int, char> i2c;</em>

<em>int ans = 0;</em>

<em>// limit: length of result</em>

<em>int limit = 0;</em>

<em>// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]  </em>

<em>bool helper(vector<string>& words, string& result, int digit, int widx, int sum) { </em>

<em>    if (digit == limit) {</em>

<em>        ans += (sum == 0);</em>

<em>        return sum == 0;</em>

<em>    }</em>

<em>    // if summation at digit position complete, validate it with result[digit].</em>

<em>    if (widx == words.size()) {</em>

<em>        if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {</em>

<em>            if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result</em>

<em>                return false;</em>

<em>            c2i[result[digit]] = sum % 10;</em>

<em>            i2c[sum%10] = result[digit];</em>

<em>            bool tmp = helper(words, result, digit+1, 0, sum/10);</em>

<em>            c2i.erase(result[digit]);</em>

<em>            i2c.erase(sum%10);</em>

<em>            ans += tmp;</em>

<em>            return tmp;</em>

<em>        } else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){</em>

<em>            if (digit + 1 == limit && 0 == c2i[result[digit]]) {</em>

<em>                return false;</em>

<em>            }</em>

<em>            return helper(words, result, digit+1, 0, sum/10);</em>

<em>        } else {</em>

<em>            return false;</em>

<em>        }</em>

<em>    }</em>

<em>    // if word[widx] length less than digit, ignore and go to next word</em>

<em>    if (digit >= words[widx].length()) {</em>

<em>        return helper(words, result, digit, widx+1, sum);</em>

<em>    }</em>

<em>    // if word[widx][digit] already mapped to a value</em>

<em>    if (c2i.count(words[widx][digit])) {</em>

<em>        if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0) </em>

<em>            return false;</em>

<em>        return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);</em>

<em>    }</em>

<em>    // if word[widx][digit] not mapped to a value yet</em>

<em>    for (int i = 0; i < 10; i++) {</em>

<em>        if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;</em>

<em>        if (i2c.count(i)) continue;</em>

<em>        c2i[words[widx][digit]] = i;</em>

<em>        i2c[i] = words[widx][digit];</em>

<em>        bool tmp = helper(words, result, digit, widx+1, sum+i);</em>

<em>        c2i.erase(words[widx][digit]);</em>

<em>        i2c.erase(i);</em>

<em>    }</em>

<em>    return false;</em>

<em>}</em>

<em>void isSolvable(vector<string>& words, string result) {</em>

<em>    limit = result.length();</em>

<em>    for (auto &w: words) </em>

<em>        if (w.length() > limit) </em>

<em>            return;</em>

<em>    for (auto&w:words) </em>

<em>        reverse(w.begin(), w.end());</em>

<em>    reverse(result.begin(), result.end());</em>

<em>    int aa = helper(words, result, 0, 0, 0);</em>

<em>}</em>

<em />

<em>int main()</em>

<em>{</em>

<em>    ans = 0;</em>

<em>    vector<string> words={"GREEN" , "BLUE"} ;</em>

<em>    string result = "BLACK";</em>

<em>    isSolvable(words, result);</em>

<em>    cout << ans << "\n";</em>

<em>    return 0;</em>

<em>}</em>

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0
2 years ago
How is ict integrated into marketing<br>​
Aleks04 [339]

Answer: The utilize of great ICT moreover moves forward client administrations and client request. From database advancement, site plan to showcase investigate, interpretation program, coordinate mail showcasing and preparing, the application of ICT is basic for a financial victory. The web is one of the ways in which media companies / businesses publicize.

Explanation:

5 0
1 year ago
provides an automated method for discovering host systems on a network. Although it doesn't necessarily discover all weaknesses,
Oxana [17]

Answer:

Network scan

Explanation:

Cyber security can be defined as preventive practice of protecting computers, software programs, electronic devices, networks, servers and data from potential theft, attack, damage, or unauthorized access by using a body of technology, frameworks, processes and network engineers.

Some examples of cyber attacks are phishing, zero-day exploits, denial of service, man in the middle, cryptojacking, malware, SQL injection, spoofing etc.

Generally, a security assessment is carried out by network security experts on a regular basis to determine potential loopholes or vulnerabilities in the information and technology (IT) infrastructure. One of the techniques or approach used in security assessment is a network scan.

A network scan is a security assessment technique used for the automatic detection of host systems on a network. Although a network scan isn't capable of discovering or detecting all the weaknesses on a network, it avails users information about the computer systems that are active on the network and what services the computer systems offer or what ports are available on them.

3 0
3 years ago
_________________ allows cloud controller to locate instances on separate zones to boost redundancy.
kogti [31]

Answer:

_____Router___ allows the cloud controller to locate instances on separate zones to boost redundancy.

Explanation:

A router, as a networking device, forwards data packets between one computer network and other networks.  With a router, one can use wired and wireless devices to connect to the Internet.  Unlike a modem, which connects the home network to a wider internet, a router can enable the networks to interact with one another without using the Internet.

8 0
3 years ago
Explain the ten characteristics of a digital computers​
Paul [167]

Answer:

The major characteristics of computers are the following:

Speed : A powerful computer is capable of executing about 3 million calculations per second.

Accuracy : A computer's accuracy is consistently high; if there are errors, they are due to errors in instructions given by the programmer.

Reliability : The output generated by the computer is very reliable as long as the data is reliable.

Memory/Storage Capacity : The computer can store large volumes of data and makes the retrieval of data an easy task.

Versatility: The computer can accomplish many different things. It can accept information through various input-output devices, perform arithmetic and logic operations, generate a variety of outputs in a variety of forms, etc.

Automation: Once the instructions are fed into computer it works automatically without any human intervention.

Diligence: A computer will never fail to perform its task due to distraction or laziness.

Convenience: Computers are usually easy to access, and allow people to find information easily that without a computer would be very difficult.

Flexibility: Computers can be used for entertainment, for business, by people who hold different ideals or who have varied goals. Almost anyone can use a computer, and computers can be used to assist with almost any goal.

<em>I hope it helps you!!!!</em>

6 0
3 years ago
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