Considering ideal gas:
PV= RTn
T= 25.2°C = 298.2 K
P1= 637 torr = 0.8382 atm
V1= 536 mL = 0.536 L
:. R=0.082 atm.L/K.mol
:. n= (P1V1)/(RT) = ((0.8382 atm) x (0.536 L))/
((0.082 atmL/Kmol) x (298.2K))
:. n= O.0184 mol
Then,
P2= 712 torr = 0.936842 atm
V2 = RTn/P2 = [(0.082atmL/
Kmol) x (298.2K) x (0.0184mol) ]/(0.936842atm)
:.V2 = 0.4796 L
OR
V2 = 479.6 ml
Answer:
Explanation: The molar mass and molecular weight of Cr2(SO3)3 is 344.182.
<u>Answer:</u> The energy of one photon of the given light is 
<u>Explanation:</u>
To calculate the energy of one photon, we use Planck's equation, which is:

where,
= wavelength of light =
(Conversion factor:
)
h = Planck's constant = 
c = speed of light = 
Putting values in above equation, we get:

Hence, the energy of one photon of the given light is 
Answer:
D is correct
Explanation:
because
we know that
density of lead is 11.36 g/cm3
and
density of tin is 7.31 g/cm3
so..
density of alloy by mixing 50/50
=(11.36+7.31)/2 g/cm3
=18.67/2 g/cm3
=9.33 g/cm3
Answer:
Solution A: crenation
Solution B: hemolysis
Solution C: hemolysis
Solution D: crenation
Solution E: crenation
Explanation:
Hemolysis is the rupturing of red blood cells, which results in the release of hemoglobin (from within the red blood cells) into the plasma. If a red blood cell is placed in a hypotonic solution, water will flow into the cell, the cell will swell and hemolysis will.
Crenation: when a red blood cell is placed in a <em>hypertonic solution (</em>such as highly saline solution), the red blood cell will lose water(osmosis) and will shrink in size. The red blood cell has undergone crenation.
In order for a red blood cell to prevent from undergoing hemolysis or crenation, the cell must be placed in an<em> isotonic solution, </em>i.e either in <u>0.9% (m/v) NaCl solution</u> or <u>5% glucose solution</u>
- Solution B and Solution C are hypotonic solution, thus red blood cell has undergone hemolysis.
- Solution A, D and E are hypertonic solution. thus red blood cell has undergone crenation