"CH3COOH + H2O CH3COO- + H3O+" is the equation among the choices given in the question <span>represents the reaction of acetic (ethanoic) acid with water. The correct option among all the options that are given in the question is the second option or option "B". I hope that the answer has helped you.</span>
Answer:
When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate.
When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose
When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid
Explanation:
When comparing propionic acid (CH₃CH₂COOH) and sodium propionate (CH₃CH₂COONa), the one that is more soluble in water sodium propionate. Because always a salt is more soluble in water than its acid (Solubility of propionic acid is 0,37g/mL and of sodium propionate is 1g/mL).
When comparing cyclohexane (C6H12) and glucose (C6H12O6), the one that is more soluble in water is glucose because cyclohexane is made from petroleum and its polarity is very low (cyclohexane is insoluble in water and solubility of glucose is 0,91g/mL).
When comparing hydrochloric acid (HCl) and ethyl chloride (CH3CH2Cl), the one that is more soluble in water is hydrochloric acid because an acid has a medium-high solubility in water but, again, an alkane derived from petroleum has very low solubility in water (hydrochloric acid has a solubility of 0,823g/mL and ethyl chloride is insoluble in water).
I hope it helps!
Answer:
B) high temperatures increase the activation energy of a reaction.
Explanation:
Ammonia is formed when the nitrogen gas is combined with hydrogen gas in a very high temperature. The high temperature increases the activation energy and nitrogen atom make chemical bonds with hydrogen atom results in the production of ammonia. At room temperature, they cannot react with each other.
Molar mass:
Ca(OH)₂ = 74.093 g/mol
Ca₃(PO₄)₂ = 310.17 g/mol
Mole ratio:
<span>2 Na</span>₃<span>PO</span>₄<span> + 3 Ca(OH)</span>₂<span> = Ca</span>₃<span>(PO</span>₄<span>)</span>₂<span> + 6 NaOH
</span>
3 x 74.093 g Ca(OH)₂ ----------- 310.17 g Ca₃(PO₄)₂
?? g Ca(OH)₂ ----------- 3.09 g Ca₃(PO₄)₂
Mass of Ca(OH)₂ = 3.09 x 3 x 74.093 / 310.17
Mas of Ca(OH)₂ = 686.84211 / 310.17
= 2.214 g of Ca(OH)₂
hope this helps!
5.5484 x 10^4
^= the tiny 4 at the top of the number
couldn't figure out how to make it so gave up
