Answer:
SeCl₆ < SeF₂ < SeO₂
Explanation:
(A) SeO₂
The central atom has 2 bond pairs and 1 lone pair. The molecule is bent shaped which has an angle of 120°.
(B) SeCl₆
The central atom has 6 bond pairs and 0 lone pair. The geometry is octahedral in which the equatorial bonds has an angle of 90° and axial bond has an angle of 90°.
(C) SeF₂
The central atom has 2 bond pairs and 2 lone pairs. The geometry is bent shape which has an angle of approximately 105.5°.
The order is:
<u>SeCl₆ < SeF₂ < SeO₂</u>
Answer:
41.45 mL
Explanation:
Applying the general gas equation,
PV/T = P'V'/T'............... Equation 1
Where P = Initial pressure of hydrogen, V = Initial volume of hydrogen, T= Initial Temperature of hydrogen, P' = Final pressure of hydrogen, V' = Final Volume of Hydrogen, T' = Final Temperature.
make V' the subject of the equation
V' = PVT'/TP'................ Equation 2
Given: P = 718 torr = (718×133.322) N/m² = 95725.196 N/m², V = 47.9 mL = 0.0479 dm³, T = 26 °C = (26+273) = 299 K, T' = 273 K, P' = 101000 N/m²
Substitute these values into equation 2
V' = ( 95725.196×0.0479×273)/(299×101000)
V' = 0.04145 dm³
V' = 41.45 mL
Answer:A chlorine atom in its ground state has a total of seven electrons in orbitals related to the atoms third energy level.
Explanation:
The presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.
The atmosphere has been divided into five layers based on the availability and the composition of different elements.
<h3>Troposphere</h3>
The troposphere has been the lowest layer of the atmosphere. It has been closed to the earth surface and provides with clouds and maintain weather.
The gases on the troposphere are used by the organisms for living purpose. The ozone has been a harmful gas for living organisms.
Thus, the presence of ozone in the troposphere has been considered as pollutant. Thus, option A is correct.
Learn more about troposphere, here:
brainly.com/question/201658
called the Avogadro number
N(A)= 6.02 x 10^23 mol^-1
1 mole of SO3 will contain 6.02 x 10^23 mol^-1 of SO3 molecules.
thus, 1.14moles will contain;
= 1.14mol x [3mol O/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 2.05884 x 10^24 oxygen atoms
= 1.14mol x [1mol S/1mol SO3] x [6.02 x 10^23
atoms O/1mol O]
= 6.8628 x 10^23 sulfur atoms
hope this helps:-)
