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Harman [31]
3 years ago
13

14. As the temperature of the reaction is increased,

Chemistry
1 answer:
AfilCa [17]3 years ago
3 0
Reactant molecules collide more frequently and with greater energy per collision
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2. Al + Fe2O3 → Al2O3 + Fe (Need to balance equation)
shtirl [24]
Balanced equation: 2Al+Fe2O3–> Al2O3+2Fe

Using mole calculations you can find that 10g of Al produces 24.3g of Fe under the conditions described
4 0
3 years ago
Carbordum is silicon carbide SiC a very hard material used as an abrasive on sand paper and in other applications. it is prepare
AleksandrR [38]

Answer:

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

Explanation:

The balanced equation for the reaction between silicon dioxide and carbon at high temperature is given as:

SiO_2+3C\rightarrow SiC+2CO

1 mole silicon dioxide reacts with 3 moles of carbon to give 1 moles of silicon carbide and 2 moles of carbon monoxide.

Mass of SiC = 3.00kg = 3000.00 g

1 kg = 1000 g

Molecular mass of SiC = 40 g/mol

Moles of SiC = \frac{3000.00 g}{40 g/mol}= 75 mol

According to reaction, 1 mole of SiC is produced from 1 mole of silicon dioxide.

Then 75 moles of SiC will be produce from:

\frac{1}{1}\times 75 mol=75 mol of silicon dioxide.

mass of 75 moles of silicon dioxde:

75 mol\times 60 g/mol=4500 g=4.5 kg

4.5 kilograms of silicon dioxide is required to produce 3.00 kg of SiC.

3 0
3 years ago
Which of the following equations does not demonstrate the law of conservation of mass
tia_tia [17]
The answer is c :) i hope its the right answer
8 0
3 years ago
Read 2 more answers
How does the chemical formula for the nitrite ion differ from the chemical formula for the nitrate ion?
Darina [25.2K]
The nitrite ion has one less oxygen than the nitrate ion. Nitrate is NO3-1 while the nitrite ion is NO2-.
8 0
3 years ago
Read 2 more answers
For the chemical reaction CaI2+2AgNO3-> 2AgI+Ca(NO3)2 how many moles of silver iodide will be produced from 205g of calcium i
Colt1911 [192]

Answer:

Moles of silver iodide produced = 1.4 mol

Explanation:

Given data:

Mass of calcium iodide = 205 g

Moles of silver iodide produced = ?

Solution:

Chemical equation:

CaI₂ + 2AgNO₃     →      2AgI + Ca(NO₃)₂

Number of moles calcium iodide:

Number of moles = mass/ molar mass

Number of moles = 205 g/ 293.887 g/mol

Number of moles = 0.7 mol

Now we will compare the moles of calcium iodide with silver iodide.

                     CaI₂         :           AgI

                         1           :             2

                       0.7         :           2×0.7 = 1.4

Thus 1.4 moles of silver iodide will be formed from 205 g of calcium iodide.

6 0
3 years ago
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