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NeX [460]
3 years ago
15

How many grams of aluminum chloride are produced when 6.73 g of aluminum react with an excess of chlorine gas?

Chemistry
1 answer:
sergejj [24]3 years ago
8 0

Answer:

33.3 g AlCl3

Explanation:

First:

You need a balanced chem equation.

2Al + 3Cl2 --->2AlCl3

So now you use this to set up train track method which helps us cancel out the units. Also we dont care about chlorine because it is excess.

6.73g Al x 1mol Al/26.98g Al x 2mol AlCl3/2molAl x 133.34g AlCl3/1molAlCl3

= 33.3 g AlCl3

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Black_prince [1.1K]
4 NH₃ + 3O₂ --> 2N₂ + 6H₂O

First, make sure that this is a balanced equation.
There are 4 moles of nitrogen on the left side, and 4 moles of nitrogen on the right side.
There are 12 moles of hydrogen on the left side, and 12 moles of hydrogen on the right side.
There are 6 moles of oxygen on the left side, and 6 moles of oxygen on the right side.

The equation is therefore balanced, and we may proceed.

a) the mole ratio for NH₃ to N₂ is 4 to 2, which can be simplified to 2:1 or 2/1.

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Given :

A 3.82L balloon filled with gas is warmed from 204.9K to 304.8 K.

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