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Ira Lisetskai [31]
3 years ago
13

Help in 5 6 and then I will help you

Mathematics
2 answers:
svlad2 [7]3 years ago
5 0
5 is rhombus and 6 is square or rectangle or both
Olenka [21]3 years ago
4 0
#5 is a Rhombus, and #6 is: She could have drawn a square or a rectangle.
You might be interested in
One postive interger is 5 less than another. The product of the two intergerd id 24. What are the intergers?
Nesterboy [21]
Your function will be 24=X+(Y+5)

to solve you subtract 5 from each side giving you 19=X+Y now you divide the 19 by 2 so you figure out the base integers giving you 9.5

now you add 5 to one of your integers meaning 9.5+5=14.5

so your integers are 9.5 and 14.5

to check this you do 14.5-9.5 which equal 5 now you do 14.5+9.5 which equals 24
4 0
3 years ago
The room of a study hall is eight feet high ceilings and it's twelve and a half ft long.
Leya [2.2K]
35.5 ft is the width of the room
4 0
3 years ago
Factor the following polynomial 9x2 + 21x – 18
solong [7]

Answer:

factors are

21 and x

Step-by-step explanation:

equation 9 × 2 + 21x - 18

terms 9 , 2, 21x, -18

factors 21x = 21 and x

4 0
3 years ago
Read 2 more answers
the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
I really need help with this problem steps
melamori03 [73]
Solve for y by setting one equation =to X after that you can substitute the equation into the other one let's set the first one in X= FORM
X-7y=10
-2x+14y=-20

Add 7y to both sides of the first equation to let x stand alone
X=7y+10
Now you can substitute x on the second equation
-2 (7y+10)+14y=-20
Distribute
-14y-20+14y=-20
Add and simplify
Us cancel out =0
-20=-20
0=0
They are the same equations you can also divide the second equation by -2 which would make it look like this
X-7y=10
-2 (x-7y=10)
Let me know if I have answered your question
5 0
3 years ago
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