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forsale [732]
4 years ago
11

Give the values of n, l and ml for: (a) each orbital in the 2p subshell, (b) each orbital in the 5d subshell.?

Chemistry
1 answer:
SCORPION-xisa [38]4 years ago
7 0

Hey there!:

* For 2p subshell :

n = 2, l =1, ml = -1, 0, +1

* for 5d subshell,

n = 5, l = 2, ml = -2, -1, 0, +1, +2


Hope that helps!

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Aluminum has the electronic configuration 2,8,3. How many valence
Klio2033 [76]

Answer:

3 valence electrons

Explanation:

Because aluminum has three, that means three fluorines can bond. The make the formula AlF3, also known as aluminum trifluoride. Each of the fluorine atoms gets an electron to fill their shell, and the aluminum loses three, giving it a filled shell too (remember, aluminum has three extra electrons).

6 0
3 years ago
What is the mass number of an isotope
makkiz [27]
<span>The mass number given on the periodic table is a weighted average of all the isotopes. You get the exact mass of an isotope by adding the protons(atomic number) to the number of neutrons in that isotope.</span>
8 0
3 years ago
Read 2 more answers
Pls help! Due today.
iragen [17]

Answer:

Explanation:

% yields =  <u>experimental yields</u> / theoretical yields )x 100%

              =( 302 ÷ 320 )x 100% = 94.4 %

% error = 100% - 94.37% 5.64%

or u can use this law :

% error =(theoretical  value - experimental value )/ theoretical value) x 100%

              ( 320 - 302 )/ 320 ) x 100% = 5.64%

8 0
3 years ago
Enough of a monoprotic acid is dissolved in water to produce a 0.0165 m solution. the ph of the resulting solution is 2.68. calc
Dmitrij [34]
Answer is: Ka for the monoprotic acid is 3.03·10⁻⁴.
<span>
Chemical reaction: HA(aq) </span>⇄ A⁻(aq) + H⁺<span>(aq).
c(monoprotic acid) = 0.0165 M.
pH = 2.68.
[A</span>⁻] = [H⁺] = 10∧(-2.68).<span>
[A</span>⁻] = [H⁺] = 0.00209 M; equilibrium concentration.<span>
[HA] = 0.0165 M - 0.00209 M.
[HA] = 0.0144 M.
Ka = [A</span>⁻]·[H⁺] / [HA].<span> 
Ka = (0.00209 M)² / 0.0144 M.
Ka = 0.000303 M = 3.03·10</span>⁻⁴<span> M.</span>
3 0
4 years ago
The medicinal thermometer commonly used in homes can be read to ±0.1°F, whereas those in the doctor's office may be accurate t
andrezito [222]

Answer:

the percent error expected from each of theses person's body:

in homes:

% E = 0.14267 %

in doctor's office:

% E = 0.257 %

Explanation:

  • ° C = ( ° F - 32 ) * (5/9)
  • % E = ( | true - exp | / true ) * 100
  • body temp = 38.9 ° C = 102.02 ° F

thermometer used in homes:

⇒ T = 102.02 ° F  +/- 0.1 ° F = 102.12 ° F ∧  101,92 ° F

⇒ T = 102.12 ° F  = 38.9555 ° C

⇒ % E = ( | 38.9 - 38.9555 | ) / 38.9 ) * 100 = 0.14267 %

in the doctor's oficce:

⇒ T = 38.9 ° C  +/- 0.1 ° C = 39 ° C ∧ 38.8 ° C

⇒ % E = (( | 39 - 38.9 | ) / 38.9 ) * 100 = 0.257 %

8 0
3 years ago
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