Question

How many moles of solute are present in a sodium chloride solution with a total

Answer 1

Answer:

n = 0.413moles (3 sig-figs).

Explanation:

From definition of molarity, solve for moles and substitute given data.

Molarity(M) = Moles Solute(n)/Volume of Solution in Liters(V)

M = n/V => n = M·V => 0.330moles/Liter x 1.25Liters = 0.4125moles ≅ 0.413moles (3 sig-figs).