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Rus_ich [418]
2 years ago
10

How many moles of solute are present in a sodium chloride solution with a total

Chemistry
1 answer:
Stella [2.4K]2 years ago
6 0

Answer:

n = 0.413moles (3 sig-figs).

Explanation:

From definition of molarity, solve for moles and substitute given data.

Molarity(M) = Moles Solute(n)/Volume of Solution in Liters(V)

M = n/V => n = M·V => 0.330moles/Liter x 1.25Liters = 0.4125moles ≅ 0.413moles (3 sig-figs).

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\boxed{3.6}

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\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}

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