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Rus_ich [418]
2 years ago
10

How many moles of solute are present in a sodium chloride solution with a total

Chemistry
1 answer:
Stella [2.4K]2 years ago
6 0

Answer:

n = 0.413moles (3 sig-figs).

Explanation:

From definition of molarity, solve for moles and substitute given data.

Molarity(M) = Moles Solute(n)/Volume of Solution in Liters(V)

M = n/V => n = M·V => 0.330moles/Liter x 1.25Liters = 0.4125moles ≅ 0.413moles (3 sig-figs).

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What is the theoretical yield of aluminum oxide if 3.00 mol of aluminum metal is exposed to 2.55 mol of oxygen?
lisabon 2012 [21]

Theoretical yield of Al₂O₃: 1.50 mol.

<h3>Explanation</h3>

2 \; \text{Al} + \dfrac{3}{2} \; \text{O}_2 \to {\bf 1} \; \text{Al}_2\text{O}_3;

4 \; \text{Al} + 3 \; \text{O}_2 \to 2 \; \text{Al}_2\text{O}_3 \; \textit{Balanced}.

How many moles of aluminum oxide formula units will be produced <em>if</em> aluminum is the limiting reactant?

Aluminum reacts to aluminum oxide at a two-to-one ratio.

3.00 \times \dfrac{1}{2} = 1.50 \; \text{mol}.

As a result, 3.00 moles of aluminum will give rise to 1.50 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced <em>if</em> oxygen is the limiting reactant?

Oxygen reacts to produce aluminum oxide at a three-to-two ratio.

2.55 \times \dfrac{2}{3} = 1.70 \; \text{mol}

As a result, 2.55 moles of oxygen will give rise to 1.70 moles of aluminum oxide.

How many moles of aluminum oxide formula units will be produced?

Aluminum is the limiting reactant. Only 1.50 moles of aluminum oxide formula units will be produced. 1.70 moles isn't feasible since aluminum would run out by the time 1.50 moles was produced.

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Rocks are classified based on
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Charge and uncharged particles
7 0
3 years ago
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Ch4+202==&gt;c02+302 what type of chemical reaction
n200080 [17]

Answer:

First of all, the equation is typed wrong so it can easily be misinterpreted

Ethane (CH4) + Oxygen gas (O2) would give us Carbon Dioxide (CO2) and WATER (H2O)

CH4 + 2O2 -----> CO2 + 2H2O

And this is a combustion reaction since we have oxygen as a reactant and carbon dioxide and water as products.

4 0
2 years ago
The possible products of a double displacement reaction in aqueous solution are SrSO4 and NaCl. Which of these possible products
madam [21]

Answer:

SrSO4

Explanation:

According to solubility rules, we know that the sulphates of the elements of group two are insoluble in water. The solubility rules describe what chemical species are soluble in water and what species are not soluble in water.

Generally, all chlorides are soluble in water with exception of chlorides such as silver chloride. The chlorides of group one elements are usually highly soluble in water.

Since SrSO4 is a sulphate of a group two element (strontium) it will be the insoluble solid product of the double displacement reaction described in the question.

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