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madam [21]
3 years ago
14

Which one of the following pair has the same number of ions?

Chemistry
2 answers:
vladimir1956 [14]3 years ago
8 0
Which one of the following pair has the same number of ions?

(c)1/2 mole of NaCl and 1/3 mole of MgCl3

Hope this helps!
zhuklara [117]3 years ago
6 0
Hahahaaaa none of the above but IF <span>(c) is
 
1/2 mole of NaCl and 1/3 mole of MgCl2 instead,

then C is the right ans :)</span>
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A helium balloon contains 16.9 L of helium at STP. How many atoms of helium are in the balloon
Zepler [3.9K]
4.54×10^(23) atoms He
8 0
3 years ago
When excess dilute hydrochloric acid was added to sodium sulphite 960 of sulphuric (iv) oxide was produced. calculate the mass o
irakobra [83]

The mass of sodium sulfite that was used will be 1,890 grams.

<h3>Stoichiometric problems</h3>

First, the equation of the reaction:

NaSO_3 + 2HCl --- > NaCl_2 + H_2O + SO_2

The mole ratio of SO2 produced and sodium sulfite that reacted is 1:1.

Mole of 960 grams SO2 = 960/64 = 15 moles

Equivalent mole of sodium sulfite that reacted = 15 moles

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More on stoichiometric problems can be found here: brainly.com/question/14465605

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3 0
2 years ago
How would you prepare 100 ml of 0.4 M MgSO4 from a stock solution of 2 M MgSO4?
miss Akunina [59]
OK, so to answer this question, you will simply use the molality equation which is as follows:
<span>M1V1 = M2V2 
In the givens you have:
M1 = 2M
V1 is the unknown
M2 = 0.4M
V2 = 100 ml

</span>plug in the givens in the above equation:
<span>2 x V1 = 0.4 x 100 
</span>therefore:
V1 = 20 ml

Based on this: you should take 20 ml of the 2 M solution and make volume exactly 100 ml in a volumetric flask by diluting in water.

7 0
3 years ago
After a product is released from its active site, a(n) ______ can be used again in another reaction because it is not consumed o
3241004551 [841]

Answer:

Enzyme.

Explanation:

Enzymes act as a catalyst in all reaction but remain unchanged by the process.

7 0
3 years ago
How many grams is 3.35 moles of hcl
lions [1.4K]
Do this

3.35mol HCl | 34.46g HCl
------------------------------------
          1          | 1mol HCl
Multiply all the numbers on top by all the numbers on bottom.

7 0
3 years ago
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