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Andrews [41]
2 years ago
7

Based on the information in the table, which elements are most likely in the same periods of the periodic table?

Chemistry
2 answers:
daser333 [38]2 years ago
3 0
The answer is A.<span>Boron and carbon are likely together in one period because they have very close atomic numbers, while gallium and germanium are likely together in another period because they have very close atomic numbers.
</span>
Stells [14]2 years ago
3 0

The element that  are most likely in the same period of periodic table is

<em> Boron  and carbon  are likely together in one period  because they  have  very close  atomic   number, while  gallium and germanium  are likely  together  in another period  because  they  have  very  close atomic  numbers ( answer A)</em>


<u>Explanation</u>

  • Element  in   same period  have the  close atomic  number .
  • The   atomic number of  an element is determined by number of protons the element have.
  • The number of proton are equal to number of electrons

Therefore   boron is in atomic number  5  with  2.3  electronic  configuration  while  carbon  is in atomic number 6 with 2.4  electron  configuration

since both  boron  and carbon  have two  energy level  they are in period 2.


Gallium  is in atomic number 31 with  2.8.8.8.5  electron configuration while Germanium (Ge)  is in atomic number 32 with  2.8.8.8.6  electron configuration.

Since  both gallium  and germanium  has 5  energy level they are in  same period (period 5)


  • for example  Aluminum,boron  and gallium are in group (iii)  since they have  3 valence electrons.
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Answer:

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Now CH₃COOH and NaOH reacts to give CH₃COONa according to the reaction :

CH₃COOH + NaOH ------> CH₃COONa + H₂O

1 mole of CH₃COOH reacts with 1 mole of NaOH to give 1 mole of CH₃COONa  

So 2.1944 millimoles of CH₃COOH will react with 2.1944 millimoles of NaOH to give 2.1944 millimoles of CH₃COONa

So all the acid (CH₃COOH) and base (NaOH) has been converted into salt (CH₃COONa) so there is no acid or base left.

Now molarity of CH₃COONa = number of millimoles of CH₃COONa/total volume in ml = 2.1944/(58.99 + 42.2) = 2.1944/101.19 = 0.02169 M

So using the hydrolysis equation :  

pH = 1/2 [ pKw + pKa + log c ]  

Ka for acetic acid = 1.75 X 10⁻⁵  

so pKa = -log (1.75 X 10⁻⁵) = 4.74  

Kw = 10⁻¹⁴

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c = 0.02169  

so log c = log 0.02169 = -1.66  

putting the values....  

pH = 1/2 [14 + 4.74 - 1.66 ]  

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