Answer:It would be orange
Explanation:I hope this helps
Answer:
Runoff from a cattle ranch
<u>Answer:</u> The solubility of oxygen at 682 torr is 
<u>Explanation:</u>
To calculate the molar solubility, we use the equation given by Henry's law, which is:

Or,

where,
are the initial concentration and partial pressure of oxygen gas
are the final concentration and partial pressure of oxygen gas
We are given:
Conversion factor used: 1 atm = 760 torr

Putting values in above equation, we get:

Hence, the solubility of oxygen gas at 628 torr is 
<h3><u>Answer;</u></h3>
<em><u> = 48,828.125 mi/hr²</u></em>
<h3><u>Explanation and solution</u>;</h3>
- <em><u>Centripetal acceleration is the rate of change of angular velocity. Centripetal acceleration occurs towards the center of the circular path along the radius of the circular path</u></em>.
- Centripetal acceleration is given by; <em>V²/r ; </em>
<em>V = 125 mi/h and r = 0.320 miles </em>
- <em>Thus; centripetal acceleration = 125²/0.320 </em>
=15625/0.320
<em><u> = 48,828.125 mi/hr²</u></em>