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VMariaS [17]
3 years ago
5

The acacia ant is a parasite on the acacia tree. True False

Physics
1 answer:
stiv31 [10]3 years ago
4 0
<em>The answer you are looking for is: </em>
<em><u>True </u></em>
<em>Hope that helps!! </em>
<em>Have a wonderful day!!</em>
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A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

      The length of string reeled in is  l  = 152 \ m

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

=>   Adj  =  114.71 \ m

3 0
3 years ago
Step by step process on how to solve this problem
rusak2 [61]

<u>Step-1:</u>  Remember or look up the formula for the force of gravity between two objects.    F = G · m₁ · m₂ / R²

<u>Step-2:</u>  Remember or look up the value of G.<em> </em> G = 6.67 x 10⁻¹¹ m³·kg/s²

<u>Step-3: </u> Write the numbers you know into the formula.

(1.989 x 10²⁰ Newtons) =

(6.67 x 10⁻¹¹ mtr³·kg/s²) · (5.9742 x 10²⁴ kg) · (moon mass) / (3.84 x 10⁸ mtr)²

<u>Step-4:</u>  Sit back, relax, take your time, look this mess over, carefully, end-to-end, and decide how to solve it for (moon mass) .

<u>Step-5:</u> Divide each side by (6.67x10⁻¹¹mtr³·kg/s²)·(5.9742x10²⁴kg)/(3.84x10⁸mtr)²:

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

<u>Step-6: </u> Crunch the numbers.  Be careful to KEEP all the units as you go along. When you're done, the units of your answer will be the first instant indication if you made a mistake.  You're looking for the MASS of the moon.  If the answer doesn't have units of 'kg', then that'll be an immediate red flag, telling you that there's been a mistake somewhere.

Moon mass =

(1.989x10²⁰ Newtons)·(3.84x10⁸ mtr)²/(6.67x10⁻¹¹ mtr³·kg/s²)·(5.9742x10²⁴ kg)

Collect the numbers, and collect the units:

Moon mass = (1.989x10²⁰ · (3.84x10⁸)² / (6.67x10⁻¹¹ · 5.9742x10²⁴)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = (1.989 · 3.84² x 10³⁶) / (6.67 · 5.9742 x 10¹³)

(kg-mtr/s² · mtr²)/(mtr³·kg/s² · kg)

Moon mass = 0.736 x 10²³ kg

Moon mass = 7.36 x 10²² kg

<u>Step 7: </u> Look it up in a book or online.  See if you're anywhere close.

When I search "moon mass" on Floogle, the first hit says

" 7.348 x 10²² kg " .

yay !  I'm satisfied.

6 0
3 years ago
A 42.2 N force acts at 40* to the ground, causing the object to move a horizontal distance of 8.15 m. How much work was done on
slavikrds [6]

Answer:

W=F.dcos angle

w=42.2 x8.15 x cos40

w=343.93× cos 40

W=343.93 x 0.76

W=261.38 J

7 0
3 years ago
What forces affect a toy car as it moves down a ramp?
Amanda [17]

Answer:

gravity

Explanation:

3 0
3 years ago
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I need help with physical science math problems
charle [14.2K]

Answer:CANT SEE THE PICTURE

ch

Explanation:

NEED A BETTER PHOTO

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3 years ago
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