Question

A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string is reeled in while bringing the kite back to the ground, what is the horizontal displacement of the kite in the process

Answer 1

Answer:

The  horizontal displacement is  $Adj = 114.71 \ m$

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  $\theta = 41 ^o$

      The length of string reeled in is  $l = 152 \ m$

     

Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     $cos \theta = \frac{Adj}{Hyp }$

substituting values

     $cos(41) = \frac{Adj}{152}$

=>   $Adj = 114.71 \ m$