The force (expressed in N), the egg experience upon hitting the ground is 3.5N.
<h3>What is Net force?</h3>
When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
Given is an 0.07 kg egg and toss if from a window 30 m above the ground. The egg reaches and maintains a falling speed of 0.5 m/sec. Upon reaching the ground, the egg rapidly decelerates to 0 m/sec over the course of only 0.01 seconds.
<h3>Average force = Mass x acceleration</h3>
F = m x (Vf -Vi)/t
F = 0.07 x (0 - 0.5)/0.01
F = -3.5N
Thus, the magnitude of force on egg upon hitting the ground is 3.5N.
Learn more about net force.
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A if it is one answer and if it’s multiple choice A and D
Answer: 2.3m/s
Explanation:
mass-energy balance: ke(f) + pe(f) = ke(o) + pe(o)
since we are looking for the point at the bottom of the pendulum, thats the reference point, the lowest in the system. pe(f) is 0, since h
ke(f)=0.5m x v(f)^2
pe(f)=0
ke(o)=0.5m x v(o)^2
pe(o)-mxgxh
find h by: drawing a triangle with the pendulum at the vertical, then displaced by 25 degrees , The difference in height is h, because cos(25)=(adj)/(hyp)=(2-h)/2. I found h=0.187m
In the m-e balance, cancel the masses in all the terms.
.5xv(f)^2 =0.5v(o)^2 +gxh
Given v(o) = 1.2 m/s and g = 9.8 then v(f) = 2.2595 m/s
Therefore V(0) = 2.3 m/s
Yes. True. Resistors slow the current down at the point in the circuit.
Hope it helps you...
( Answered by Benjemin )
Since the gravitational potential energy of an object is directly proportional to its height above the zero position, a doubling of the height will result in a doubling of the gravitational potential energy. A tripling of the height will result in a tripling of the gravitational potential energy.
