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dimulka [17.4K]

3 years ago

12

A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string

is reeled in while bringing the kite back to the ground, what is the horizontal displacement of the kite in the process

1 answer:

satela [25.4K]3 years ago

3 0

Answer:

The horizontal displacement is $Adj = 114.71 \ m$

Explanation:

From the question we are told that

The angle at which the string is maintained is $\theta = 41 ^o$

The length of string reeled in is $l = 152 \ m$

Using the SOHCAHTOA formula

We have that the hypotenuse(Hyp) is l = 152

Hence the horizontal displacement of the kite which is the Adjacent(Adj) can be evaluated as

$cos \theta = \frac{Adj}{Hyp }$

substituting values

$cos(41) = \frac{Adj}{152}$

=> $Adj = 114.71 \ m$

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Explanation:

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We know that,

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Coefficient of linear expansion of steel is

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$\Delta l=l\times\alpha\times\Delta t$

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