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adell [148]
3 years ago
7

Gravity is greater when there is

Physics
1 answer:
Papessa [141]3 years ago
4 0
-- more mass involved

-- less distance between the two objects
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Which of the following is NOT a layer of the Sun?
Alja [10]
It depends when you look at a pichture it could possibly help.
3 0
3 years ago
One end of a rope is tied to the handle of a horizontally-oriented and uniform door. a force f is applied to the other end of th
Vlada [557]

For rotational equilibrium of the door we can say that torque due to weight of the door must be counter balanced by the torque of external force

F\times L = mg \times \frac{L}{2}

here weight will act at mid point of door so its distance is half of the total distance where force is applied

here we know that

mg = 145 N

now we will have

F = \frac{mg}{2}

F = \frac{145}{2} = 72.5 N

so our applied force is 72.5 N

7 0
3 years ago
A 20.0-N weight slides down a rough inclined plane which makes an angle of 30 degree with the horizontal. The weight starts from
Ulleksa [173]

Answer:

1270.64\ \text{J}

Explanation:

m = Mass of object = \dfrac{mg}{g}

mg = Weight of object = 20 N

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

v = Final velocity = 15 m/s

u = Initial velocity = 0

d = Distance moved by the object = 150 m

\theta = Angle of slope = 30^{\circ}

f = Force of friction

fd = Work done against friction

The force balance of the system is

\dfrac{1}{2}m(v^2-u^2)=(mg\sin\theta-f)d\\\Rightarrow \dfrac{1}{2}mv^2=mg\sin\theta d-fd\\\Rightarrow fd=mg\sin\theta d-\dfrac{1}{2}mv^2\\\Rightarrow fd=20\times \sin 30^{\circ}\times 150-\dfrac{1}{2}\times \dfrac{20}{9.81}\times 15^2\\\Rightarrow fd=1270.64\ \text{J}

The work done against friction is 1270.64\ \text{J}.

8 0
3 years ago
A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the e
andrew-mc [135]
Average velocity = (x( 2.08 ) - x ( 0 )) / ( 2.08 s - 0 s )
x ( 2.08 ) = 1.42 * 2.08² - 0.05 * 2.08³ =
= 1.42 * 4.3264 - 0.443456 = 6.143484 - 0.443456 ≈ 5.7 m
v = ( 5.7 m - 0 m) / (2.08 s - 0 s ) = 5.7 / 2.08 m/s = 27.4 m/s
3 0
3 years ago
If an object undergoes a change in momentum of 10 kg m/s in 3 s ,then the force acting on it is
Paha777 [63]

Answer:

Force = 3.333 Newton

Explanation:

Given the following data;

Change in momentum = 10 Kgm/s

Time = 3 seconds

To find the force acting on it;

In Physics, the change in momentum of a physical object is equal to the impulse experienced by the physical object.

Mathematically, it is given by the formula;

Force * time = mass * change in velocity

Impulse = force * time

Substituting into the formula, we have;

10 = force * 3

Force = 10/3

Force = 3.333 Newton

8 0
3 years ago
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