Kinetic energy lost in collision is 10 J.
<u>Explanation:</u>
Given,
Mass,
= 4 kg
Speed,
= 5 m/s
= 1 kg
= 0
Speed after collision = 4 m/s
Kinetic energy lost, K×E = ?
During collision, momentum is conserved.
Before collision, the kinetic energy is

By plugging in the values we get,

K×E = 50 J
Therefore, kinetic energy before collision is 50 J
Kinetic energy after collision:


Since,
Initial Kinetic energy = Final kinetic energy
50 J = 40 J + K×E(lost)
K×E(lost) = 50 J - 40 J
K×E(lost) = 10 J
Therefore, kinetic energy lost in collision is 10 J.
Answer:
150J
Explanation:
Formula : <u>Work</u><u> </u><u>done</u>
Force x distance
work done = force x distance
Distance should be measured in meters
300÷100=3m
work done = 450 x 3
=150J
Answer:
416.667 m/s
Explanation:
divide the distance by the time
Answer:
Total electric potential, 
Explanation:
It is given that,
First charge, 
Second charge, 
Distance of first charge from origin, 
Distance of second charge from origin, 
We need to find the total electric potential at the origin. The electric potential at the origin is given by :



V = 1321826.08 V
or

So, the total electric potential at the origin is
. Hence, this is the required solution.