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BigorU [14]
3 years ago
14

Weight refers to the force of gravity acting on a mass. We often calculate the weight of an object by multiplying its mass by th

e local acceleration due to gravity. The value of gravitational acceleration on the surface of Mars is 0.377 times that on Earth. If your mass is 85 kg, your weight on Earth is 830 N (m × g = 85 kg × 9.8 m/s² = 830 N). What would be your approximate mass and weight on Mars?
Physics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

85 Kg

314.041 N

Explanation:

We are given that

Mass  of body on earth=85 kg

Acceleration due to gravity on earth=9.8 m/s^2

Weight of body on earth=830 N

We have to find the mas of body and weight of body on Mars.

We know that mass of an object does not change with location .

It remain same everywhere.

Mass of body on Mars=85 kg

Gravitational acceleration on the surface of Mars=0.377 \times 9.8=3.6946 m/s^2

We know that

Weight =mg

Using this formula

Weight of body=3.6946\times 85=314.041 N

Hence, the weight of body on Mars=314.041 N

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It seems that you have missed the necessary options for us to answer this question so I had to look for it. Anyway, the answer to the given statement is FALSE. Pigments are NOT always made of natural materials. Pigments can either be man-made or the one that occurred naturally as what you see in our environment. Hope this helps.
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How important is education in helping to prevent pregnancy and the spread of STD’s?
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Answer:

If children are not taught about the spread of STD's,future generations will not know how to stop them.

Explanation:

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3 years ago
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Firdavs [7]

1). The forces inside the atom are always, totally, completely, electrostatic forces. Those are so awesomely stronger than the gravitational forces that the gravitational ones are totally ignored, and it doesn't change a thing.

Parts 2 and 3 of this question are here to show us how the forces compare.

Part-2). The electrostatic force between a proton and an electron.

The constant in the formula is 9x10^9, and the elementary charge is 1.602 x 10^-19 Coulomb ... same charge on both particles, but opposite signs.

I worked through it 3 times and got 0.000105 N every time. So the best choice is 'C', even though we disagree by a factor of ten times. You'll see in part-3 that it really doesn't make any difference.

Part-3). Gravitational force between a proton and an electron.

The constant in Newton's gravity formula is 6.67x10^-11 . You'll have to look up the masses of the proton and the electron.

I got 2.163 x 10^-55 N ... exactly choice-C. yay !

Now, after we've slaved over a hot calculator all night, the thing that really amazes us is not only that the electrostatic force is stronger than the gravitational force, but HOW MUCH stronger ... 10^51 TIMES stronger. That's a thousand trillion trillion trillion trillion times stronger !

That's why it has no effect on the measurements if we just forget all about the gravitational forces inside the atom.

4 0
3 years ago
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If a force of 10 n is applied to an object with a mass of 1kg the object will accelerate at
givi [52]
We Know, F = m*a
Here, F = 10 N
m = 1 Kg

Substitute their values in the equation,
10 = 1 * a
a = 10/1
a = 10

So, your final answer & the acceleration of the object would be 10 m/s²

Hope this helps!
3 0
3 years ago
A 1500 kg weather rocket accelerates upward at 10.0 m/s . It explodes 2.00 s after liftoff and breaks into two fragments, one tw
serious [3.7K]

20 m/s is the speed of the heavier fragment just after the explosion.

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = ma                   where, F = Force (Newton)

                                          m= mass

                                          a = acceleration

Given:

mass of rocket = M = 1500 kg

acceleration of rocket = a = 10 m/s²

elapsed time = t = 2.00 s

mass of lighter fragment = m₁ = m = 500 kg

mass of heavier fragment = m₂ = 2m = 1000 kg

maximum height of lighter fragment = h = 530 m

Let's calculate the final speed of the rocket just before the explosion:

v = u + at

v = 0 + 10(2)

v = 20 m/s

Then, we will calculate the height of the rocket just before the explosion:

h' = ut + \frac{1}{2}at^{2}

h' = 0 + \frac{1}{2} (10)(2.00)^{2}

h' =20m

The initial speed of lighter fragment just after the explosion:

v^{2}₁ = u^{2}₁ - 2gΔh

v^{2}₁ = u^{2}₁ - 2g (h - h')

0^{2} = u^{2}₁- 2(9.8) (530-20)

u^{2}₁=9996

u₁ =\sqrt{9996}  m/s

Using Conservation of Momentum Law :

M v=m₁ u₁ +  m₂u₂

1500 (20)= 500(\sqrt{9996} ) + 1000u₂

u₂ ≅ - 20 m/s

Learn more about Newton's law of motion here:

brainly.com/question/10454047

#SPJ4

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