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BigorU [14]
3 years ago
14

Weight refers to the force of gravity acting on a mass. We often calculate the weight of an object by multiplying its mass by th

e local acceleration due to gravity. The value of gravitational acceleration on the surface of Mars is 0.377 times that on Earth. If your mass is 85 kg, your weight on Earth is 830 N (m × g = 85 kg × 9.8 m/s² = 830 N). What would be your approximate mass and weight on Mars?
Physics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

85 Kg

314.041 N

Explanation:

We are given that

Mass  of body on earth=85 kg

Acceleration due to gravity on earth=9.8 m/s^2

Weight of body on earth=830 N

We have to find the mas of body and weight of body on Mars.

We know that mass of an object does not change with location .

It remain same everywhere.

Mass of body on Mars=85 kg

Gravitational acceleration on the surface of Mars=0.377 \times 9.8=3.6946 m/s^2

We know that

Weight =mg

Using this formula

Weight of body=3.6946\times 85=314.041 N

Hence, the weight of body on Mars=314.041 N

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Answer:

silicon is the second most abundant element in Earth’s crust. It is found in the sun and stars; and in clay which is used to make pottery.

Explanation:

6 0
3 years ago
PLEASE HELP IN ONE MINUTE
Greeley [361]
I think it’s 8 hours. I’m sorry if I’m wrong.
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4 0
3 years ago
Propose a hypothesis for how the position of the ball will affect the amount of its gravitational pull energy
Ray Of Light [21]

<em><u>throwing a ball up initially has a lot of kinetic energy because it is moving upwards ( kinetic energy is energy which a body possesses by virtue of being in motion.) this all then get converted to gravitational potential energy, and for a moment it is stationary before it begins to fall again.  by the time it has returned again, all the gravitational potential energy has turned back into kinetic.</u></em>

4 0
3 years ago
A 125-kg astronaut (including space suit) acquires a speed of 2.50 m/s by pushing off with her legs from a 1900-kg space capsule
ryzh [129]

(a) 0.165 m/s

The total initial momentum of the astronaut+capsule system is zero (assuming they are both at rest, if we use the reference frame of the capsule):

p_i = 0

The final total momentum is instead:

p_f = m_a v_a + m_c v_c

where

m_a = 125 kg is the mass of the astronaut

v_a = 2.50 m/s is the velocity of the astronaut

m_c = 1900 kg is the mass of the capsule

v_c is the velocity of the capsule

Since the total momentum must be conserved, we have

p_i = p_f = 0

so

m_a v_a + m_c v_c=0

Solving the equation for v_c, we find

v_c = - \frac{m_a v_a}{m_c}=-\frac{(125 kg)(2.50 m/s)}{1900 kg}=-0.165 m/s

(negative direction means opposite to the astronaut)

So, the change in speed of the capsule is 0.165 m/s.

(b) 520.8 N

We can calculate the average force exerted by the capsule on the man by using the impulse theorem, which states that the product between the average force and the time of the collision is equal to the change in momentum of the astronaut:

F \Delta t = \Delta p

The change in momentum of the astronaut is

\Delta p= m\Delta v = (125 kg)(2.50 m/s)=312.5 kg m/s

And the duration of the push is

\Delta t = 0.600 s

So re-arranging the equation we find the average force exerted by the capsule on the astronaut:

F=\frac{\Delta p}{\Delta t}=\frac{312.5 kg m/s}{0.600 s}=520.8 N

And according to Newton's third law, the astronaut exerts an equal and opposite force on the capsule.

(c) 25.9 J, 390.6 J

The kinetic energy of an object is given by:

K=\frac{1}{2}mv^2

where

m is the mass

v is the speed

For the astronaut, m = 125 kg and v = 2.50 m/s, so its kinetic energy is

K=\frac{1}{2}(125 kg)(2.50 m/s)^2=390.6 J

For the capsule, m = 1900 kg and v = 0.165 m/s, so its kinetic energy is

K=\frac{1}{2}(1900 kg)(0.165 m/s)^2=25.9 J

3 0
4 years ago
A 1kw electric heater is switched on for ten minutes. how much heat does it produce​
Ainat [17]

H= P × t

1kW= 1000w

10 min = 600s

H= 1000×600=600,000J

=> 143.40kcal

4 0
3 years ago
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