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Aleks04 [339]
3 years ago
8

A line is defined by the equation y=2/3x-6. The line passes through a point whose y-coordinate is 0. What is the x-coordinate of

this point?
Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

x=9

Step-by-step explanation:

To find the x-coordinate, plug the y-coordinate into the equation and solve from there.

(0 = 2/3x - 6)  (6 = 2/3x)  (18 = 2x)  9 = x

Debora [2.8K]3 years ago
6 0

Answer:

The value of x is 9 when y=0

x-coordinate is 9

Passing point (9,6)

Step-by-step explanation:

We are given the equation of line y=\frac{2}{3}x-6

The line passes through a point whose y-coordinate is 0.

We need to find x-coordinate of passing point whose y-coordinate is 0.

Put y=0 into the equation of line and solve for x

0=\frac{2}{3}x-6

6=\frac{2}{3}x

x=3\times 3 = 9

Passing point (9,6)

Hence, The value of x is 9 when y=0

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Answer:

Example 1

A backyard farmer wants to enclose a rectangular space for a new garden. She has purchased 80 feet of wire fencing to enclose 3 sides, and will put the 4th side against the backyard fence. Find a formula for the area enclosed by the fence if the sides of fencing perpendicular to the existing fence have length

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In a scenario like this involving geometry, it is often helpful to draw a picture. It might also be helpful to introduce a temporary variable,

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Example 2

Returning to our backyard farmer from the beginning of the section, what dimensions should she make her garden to maximize the enclosed area?

Earlier we determined the area she could enclose with 80 feet of fencing on three sides was given by the equation

A(L) = 80L – 2L2. Notice that quadratic has been vertically reflected, since the coefficient on the squared term is negative, so the graph will open downwards, and the vertex will be a maximum value for the area.

In finding the vertex, we take care since the equation is not written in standard polynomial form with decreasing powers. But we know that

a is the coefficient on the squared term, so a = -2, b = 80, and c = 0.

Finding the vertex:

h

=

−

80

2

(

−

2

)

=

20

,

k

=

A

(

20

)

=

80

(

20

)

−

2

(

20

)

2

=

800

The maximum value of the function is an area of 800 square feet, which occurs when

L = 20 feet. When the shorter sides are 20 feet, that leaves 40 feet of fencing for the longer side. To maximize the area, she should enclose the garden so the two shorter sides have length 20 feet, and the longer side parallel to the existing fence has length 40 feet.

Example 3

A ball is thrown upwards from the top of a 40 foot high building at a speed of 80 feet per second. The ball’s height above ground can be modeled by the equation

H(t) = –16t2 + 80t + 40.

What is the maximum height of the ball?

When does the ball hit the ground?

To find the maximum height of the ball, we would need to know the vertex of the quadratic.

h

=

−

80

2

(

−

16

)

=

80

32

=

5

2

,

k

=

H

(

5

2

)

=

−

16

(

5

2

)

2

+

80

(

5

2

)

+

40

=

140

The ball reaches a maximum height of 140 feet after 2.5 seconds.

To find when the ball hits the ground, we need to determine when the height is zero—when

H(t) = 0. While we could do this using the transformation form of the quadratic, we can also use the quadratic formula:

t

=

−

80

±

√

80

2

−

4

(

−

16

)

(

40

)

2

(

−

16

)

=

−

80

s

q

r

t

8960

−

32

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t

=

−

80

−

s

q

r

t

8960

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a

p

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r

o

x

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