1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
puteri [66]
2 years ago
13

Chemistry help!

Chemistry
1 answer:
Norma-Jean [14]2 years ago
3 0

Refer to the attachment.

Hope this helps you...

You might be interested in
How much cooking liquid is needed when employing the pasta method?
Sonbull [250]
A l l of IT? idk im 7
8 0
3 years ago
Read 2 more answers
What happens to the energy of an electron if it moves from one energy level to another
Zigmanuir [339]

Answer:

The energy levels in an atom are similar to the rungs of a ladder, but they get closer together as they get farther from the nucleus. For an electron to move from one energy level to the next higher level, it must gain the right amount of energy. If less than that amount is available, the electron stays where it is.

Explanation:

Hope this helped! Goodluck on your test or whatever you're doing! Stay safe ♥♥♥

6 0
3 years ago
Read 2 more answers
What is inside the nucleus of an atom
Tamiku [17]
The nucleus of a atom contains the protons and the neutrons all most all of the atoms mass is weigh by the protons and the neurons.
3 0
3 years ago
Read 2 more answers
You calculate that your semester average in history is 97.5. When you get your report card, your average is 96. What was the per
andrew11 [14]
Ok percent error is abs(calculated-actual)/actual(100%)

So 1.5/96 *100%
5 0
3 years ago
Read 2 more answers
An analytical chemist weighs out 0.093g of an unknown monoprotic acid into a 250mL volumetric flask and dilutes to the mark with
Kamila [148]

Answer:

The molar mass of the unknown acid is 89 g/mol

Explanation:

<u>Step 1:</u> The balanced equation

HA(aq) + NaOH(aq) → NaA(aq) + H2O(l)

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

<u>Step 2:</u> Data given

Mass of the acid = 0.093 grams

volume = 250 mL

titrates with 0.16 M NaOH

adds 6.5 mL NaOH

<u>Step 3: </u>Calculate moles of NaOH

We know the concentration and volume of NaOH needed to neutralize the acid.

By determining the moles of NaOH in that volume in liters (95.9mL=0.0959L), the moles of acid in the original sample can be determined from the reaction stoichiometry.

Moles = Molarity * Volume

Moles = 0.16 M * 0.0065 L

Moles = 0.00104 moles NaOH

<u>Step 4: </u>Calculate moles of the unknown acid:

It takes 1 mole of NaOH to neutralize 1 mole of the triprotic acid. This is called the reaction stoichiometry.

For 0.00104 moles NaOH we have 0.00104 moles of HA

<u>Step 5: </u>Calculate the molar mass of the acid

Molar mass Ha = Mass Ha / moles Ha

Molar mass Ha = 0.093 grams / 0.00104 moles

Molar mass Ha = 89.42 g/mol ≈89 g/mol

The molar mass of the unknown acid is 89 g/mol

3 0
3 years ago
Other questions:
  • Help pleas I dont understand
    11·2 answers
  • If you need to measure the mass of a greeting card you are sending to a friend through the mail, what unit of measurement would
    11·1 answer
  • Which element would most likely have a positive electron affinity
    6·1 answer
  • What is a claim?
    12·2 answers
  • The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge
    15·1 answer
  • Name some uses of Chlorine and bromine compounds
    8·1 answer
  • Antibiotics should be taken only on the advice of a qualified doctor. Also, you must complete the course prescribed by the docto
    13·1 answer
  • Water is amphoteric. If it reacts with a compound that is a stronger acid than itself, water acts as a
    12·1 answer
  • Is a instant cold pack Endothermic or Exothermic reaction? Explain.
    14·1 answer
  • Is energy needed to break the bond? Cl2 ----&gt;2Cl-​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!