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3 years ago

A cual grupo pertenecen las tierras raras y los elementos representativos??

Chemistry

1 answer:

lidiya [134]3 years ago

4 0

Answer:

Explanation:

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What is the molar mass of AgF. 51.9g/mol 198.8g/mol 126.87g/mol 99.7g/mol

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Just find Ag and F on periodic table, find g/mol for each one and add them together

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3 years ago

Will GIVE BRAINLIEST --A student makes a standard solution of potassium hydroxide by adding 14.555 g to 500.0 mL of water. Answe

leva [86]

Answer:

0.5188 M or 0.5188 mol/L

Explanation:

Concentration is calculated as molarity, which is the number of moles per litre.

***Molarity is represented by either "M" or "c" depending on your teacher. I will use "c".

The formula for molarity is:

$c = \frac{n}{V}$

n = moles (unit mol)

V = volume (unit L)

Find the molar mass (M) of potassium hydroxide.

$M_{KOH} = \frac{39.098 g}{mol}+\frac{16.000 g}{mol}+\frac{1.008 g}{mol}$

$M_{KOH} = 56.106 \frac{g}{mol}$

Calculate the moles of potassium hydroxide.

$n_{KOH} = \frac{14.555 g}{1}*\frac{1mol}{56.106g}$

$n_{KOH} = 0.25941(9)mol$

Carry one insignificant figure (shown in brackets).

Convert the volume of water to litres.

$V = \frac{500.0mL}{1}*\frac{1L}{1000mL}$

$V = 0.5000L$

Here, carrying an insignificant figure doesn't change the value.

Calculate the concentration.

$c = \frac{n}{V}$

$c = \frac{0.25941(9)mol}{0.5000 L}$

$c = 0.5188(3) \frac{mol}{L}$ <= Keep an insignificant figure for rounding

$c = 0.5188 \frac{mol}{L}$ <= Rounded up

$c = 0.5188M$ <= You use the unit "M" instead of "mol/L"

The concentration of this standard solution is 0.5188 M.

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2 years ago

A rock is found to have a mass of 200 g and a volume of 100 ml. what is the rock's density?

GaryK [48]

Mass over volume
200 over100
2

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3 years ago

Determine the [h3o+] of a 0.210 m solution of formic acid.

Nataly [62]

When the Pka for formic acid = 3.77
and Pka = -㏒ Ka
3.77 = -㏒ Ka
∴Ka = 1.7x10^-4

when Ka = [H+][HCOO-}/[HCOOH]

when we have Ka = 1.7x10^-4 &[HCOOH] = 0.21 m
so by substitution: by using ICE table value
1.7x10^-4 = X*X / (0.21-X)
(1.7x10^-4)*(0.21-X) = X^2 by solving this equation for X

∴X = 0.0059
∴[H+] = 0.0059
∴PH= -㏒ [H+]
= -㏒ 0.0059
= 2.23

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2 years ago

Two forces are acting on a wheelbarrow.One force is pushing to the right and an equal force is pushing to the left.What can you

andreev551 [17]

B. It is not accelerating since equal and opposite forces cancel each other. Hope it helps

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3 years ago

Read 2 more answers

A cual grupo pertenecen las tierras raras y los elementos representativos??​

A cual grupo pertenecen las tierras raras y los elementos representativos??