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lana66690 [7]
3 years ago
7

What of an acid and a base is determined by how completely they dissociate in water ?

Chemistry
2 answers:
Ronch [10]3 years ago
7 0

Explanation:

  • If an acid is strong in nature then upon dissolving in water it will completely dissociate into ions.

For example, HCl is a strong acid and when we dissolve it in water then it will dissociate into hydrogen (H^{+}) and chlorine (Cl^{-}) ions.

            HCl + H_{2}O \rightarrow H^{+} + Cl^{-}

  • And, if an acid is weak in nature then it will partially dissociate into ions.

For example, acetic acid is a weak acid and it will dissociate as follows when dissolved in water.

CH_{3}COOH + H_{2}O \rightleftharpoons CH_{3}COO^{-} + H^{+}

  • Similarly, if a base is strong in nature then it will completely dissociate into ions.

For example, NaOH is a strong base and when it is added to water it will dissociate as follows.

        NaOH + H_{2}O \rightarrow Na^{+} + OH^{-}

  • And, when a base is weak in nature then it will partially dissociate upon dissolution in water.

For example, ammonia is a weak base and it will dissociate as follows when added to water.

      NH_{3} + H_{2}O \rightleftharpoons NH^{+}_{4} + OH^{-}

Shtirlitz [24]3 years ago
5 0
The strength <span>of an acid and a base is determined by how completely they dissociate in water.

- - -
Strong acids (like stomach acid) break down or dissociate in water. Weak acids  maintains their protons in water.
</span>
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Si2Br6 compound name
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Answer:

disilicon hexabromide

Explanation:

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2 years ago
Need help asap with this chemistry if someone could help me
Burka [1]

Answer:

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

Structure Number Two would likely be the most stable structure.

<h3>2)</h3>
  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

The N atom is the one that is "likely" to be attracted to an anion. See explanation.

Explanation:

When calculating the formal charge for an atom, the assumption is that electrons in a chemical bond are shared equally between the two bonding atoms. The formula for the formal charge of an atom can be written as:

\text{Formal Charge} \\ = \text{Number of Valence Electrons in Element} \\ \phantom{=}-\text{Number of Chemical Bonds} \\\phantom{=} - \text{Number of nonbonding Lone Pair Electrons}.

For example, for the N atom in structure one of the first question,

  • N is in IUPAC group 15. There are 15 - 10 = 5 valence electrons on N.
  • This N atom is connected to only 1 chemical bond.
  • There are three pairs, or 6 electrons that aren't in a chemical bond.

The formal charge of this N atom will be 5 - 1 - 6 = -2.

Apply this rule to the other atoms. Note that a double bond counts as two bonds while a triple bond counts as three.

<h3>1)</h3>

Structure One:

  • N: -2
  • C: 0
  • O: +1

Structure Two:

  • N: 0
  • C: 0
  • O: -1

Structure Three:

  • N: -1
  • C: 0
  • O: 0.

In general, the formal charge on all atoms in a molecule or an ion shall be as close to zero as possible. That rules out Structure number one.

Additionally, if there is a negative charge on one of the atoms, that atom shall preferably be the most electronegative one in the entire molecule. O is more electronegative than N. Structure two will likely be favored over structure three.

<h3>2)</h3>

Similarly,

  • All five C atoms: 0
  • All six H atoms to C: 0
  • N atom: +1.

Assuming that electrons in a chemical bond are shared equally (which is likely not the case,) the nitrogen atom in this molecule will carry a positive charge. By that assumption, it would attract an anion.

Note that in reality this assumption seldom holds. In this ion, the N-H bond is highly polarized such that the partial positive charge is mostly located on the H atom bonded to the N atom. This example shows how the formal charge assumption might give misleading information. However, for the sake of this particular problem, the N atom is the one that is "likely" to be attracted to an anion.

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Answer:

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Project the image Endothermic Dissolving.

The process of dissolving is endothermic when less energy is released when water molecules “bond” to the solute than is used to pull the solute apart. Because less energy is released than is used, the molecules of the solution move more slowly, making the temperature decrease.

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Answer:

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