Answer:
E = 1.602v
Explanation:
Use the Nernst Equation => E(non-std) = E⁰(std) – (0.0592/n)logQc …
Zn⁰(s) => Zn⁺²(aq) + 2 eˉ
2Ag⁺(aq) + 2eˉ=> 2Ag⁰(s)
_____________________________
Zn⁰(s) + 2Ag⁺(aq) => Zn⁺²(aq) + 2Ag(s)
Given E⁰ = 1.562v
Qc = [Zn⁺²(aq)]/[Ag⁺]² = (1 x 10ˉ³)/(0.150)² = 0.044
E = E⁰ -(0.0592/n)logQc = 1.562v – (0.0592/2)log(0.044) = 1.602v
Assuming ammonia is the product of this reaction:
N2+3H2--->2NH3
2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2
You would need 6 mol of hydrogen gas to completely react with 2 mol of nitrogen.
Answer: A index fossil is any animal or plant preserved in the rock record of the earth that is characteristic of a particular span of geologic time or environment. A useful index fossil must be distinctive or easily recognizable, abundant, and have a wide geographic distribution and a short range through time.
Explanation:
Answer:
The ratio of staggered to eclipsed conformers is 134
Explanation:
It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:
Staggered ⇄ Eclipsed
Keq = [Eclipsed] / [Staggered]
That means Keq is equal to the ratio we need to find:
Using:
G˚= -RTln Keq
<em>Where G° = -12133.6J/mol</em>
<em>R is gas constant: 8.314J/molK</em>
<em>T is absolute temperature: 298K</em>
<em />
-12133.6J/mol= -8.314J/molK*298K ln Keq
4.8974 = ln Keq
134 = Keq = [Eclipsed] / [Staggered]
<h3>The ratio of staggered to eclipsed conformers is 134</h3>
