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monitta
2 years ago
8

According to the VSEPR theory, which of the following factors determines the shape of a

Chemistry
1 answer:
Gala2k [10]2 years ago
4 0

Answer:

B only

Explanation:

Using the VSEPR principle, the electron bond pairs and the lone pairs on the middle atom help us predict the structure of the molecule. The shape of a molecule is determined by the position of the nucleus and its electrons. The electrons and the nucleus settle in positions that minimize repulsion and maximize attraction.

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What was the main reason why Alfred Wegener's theory about the movement of the continents was dismissed in 1912?
eduard

Answer:

His map of the ocean floor did not support his theory

Explanation:

  • Alfred Wegner was a great scientist
  • He observed the plate tectonics of earth and described it in a theory.
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2 years ago
You have three elements, A, B, and C, with the following electronegativity values:
DerKrebs [107]

#AB

Electronegativity difference=3.3-2.9=0.4.

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2 years ago
What is the answer to “An element is:”
Jobisdone [24]
A. A pure chemical substance consisting of one type of atom
8 0
2 years ago
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2 Points<br> Which of the following is a thermal conductor?
yaroslaw [1]

Answer:

Metals are thermal conductor.

8 0
2 years ago
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The concentration of Rn−222 in the basement of a house is 1.45 × 10−6 mol/L. Assume the air remains static and calculate the con
bonufazy [111]

<u>Answer:</u> The concentration of radon after the given time is 3.83\times 10^{-30}mol/L

<u>Explanation:</u>

All the radioactive reactions follows first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

We are given:

t_{1/2}=3.82days

Putting values in above equation, we get:

k=\frac{0.693}{3.82}=0.181days^{-1}

Rate law expression for first order kinetics is given by the equation:

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,  

k = rate constant = 0.181days^{-1}

t = time taken for decay process = 3.00 days

[A_o] = initial amount of the reactant = 1.45\times 10^{-6}mol/L

[A] = amount left after decay process =  ?

Putting values in above equation, we get:

0.181days^{-1}=\frac{2.303}{3.00days}\log\frac{1.45\times 10^{-6}}{[A]}

[A]=3.83\times 10^{-30}mol/L

Hence, the concentration of radon after the given time is 3.83\times 10^{-30}mol/L

7 0
3 years ago
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