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3 years ago

8

According to the VSEPR theory, which of the following factors determines the shape of a

1 answer:

Gala2k [10]3 years ago

4 0

Answer:

B only

Explanation:

Using the VSEPR principle, the electron bond pairs and the lone pairs on the middle atom help us predict the structure of the molecule. The shape of a molecule is determined by the position of the nucleus and its electrons. The electrons and the nucleus settle in positions that minimize repulsion and maximize attraction.

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Which of these is an example of a chemical change?

Elena-2011 [213]

Answer:

D. Burning a peice of wood

Explanation:

Because when you burn wood a chemical reaction happenes between the flames and the wood making the wood into ashes.

Hope this helps you :)

3 0

3 years ago

So I am lost and I don't know how what any of those conversion factor things are and I'm wondering how to do #2,3, and 4. (I did

dalvyx [7]

Explanation:

#2.

A centigram is 1/100 of a gram, so that means a gram equals 100 centigrams.

Therefore you multiply 72.4 grams by 100/1 (or just 100), and get 7240 cg.

You did that one right but put the wrong unit in the answer. It is is cg ( centigrams).

#3.

1 liter is equal to 1000 milliliters, and I kiloliter is equal to 1000 liters. So one kiloliter is 1000*1000 milliliters or 1,000,000 milliliters.

The conversion factor would be

1/1000000

#4.

1 gigabyte is equal to 10^9 bytes.

I byte is equal to 10^9 bytes.

So 1 gigabyte is 10^9 * 10^9 nanobytes, or 10^18.

The conversion factor would be (1*10^18)/1.

6 0

3 years ago

How many molecules of O2 will be required to produce 28.8 g of water?

Mrac [35]

I think 1.67 x 10^20

5 0

3 years ago

Most cars use water to cool their engines. Ethylene glycol, propylene glycol, or methanol may be added to the water, especially

NemiM [27]

Answer:

B

Explanation:

8 0

3 years ago

58. A cylinder of a gas mixture used for calibration of blood gas analyzers in medical laboratories contains 5.0% CO2, 12.0% O2,

erica [24]

<em><u>Answer and Explanation:</u></em>

$Greetings!$

$Let's~answer~your~question!$

$Partial ~pressure ~of ~gas ~can ~be ~directly~ calculated ~by ~multiplying ~the~ percentage\\ of~ pressure~ of~ gases~ to ~the ~total ~pressure.$

$\boxed{Pgas~ = ~P~total~ * \% ~P ~of ~gas}$

<em><u>For % of N2 gas: </u></em>

<em><u /></em> $100\% - (5\% + 12\%) = 83\% ~N2$ <em><u /></em>

<em><u /></em>

<em><u /></em> $PN_2 ~= ~146~ atm~ *~ 0.83 ~ = 121.18 ~atm$ <em><u /></em>

<em><u /></em> $PO_2 ~= ~146~ atm~ *~ 0.12~ = 17.52 ~atm$ <em><u /></em>

<em><u /></em> $~PCO_2~ = ~146~ atm ~* 0.05 = 7.3 ~atm$ <em><u /></em>

3 0

3 years ago