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kherson [118]
4 years ago
7

List at least one reason for not touching the magnesium metal with bare hands. 3. list two reasons for using crucible tongs to h

andle the crucible and lid after their initial firing in the experimental procedure.
Chemistry
2 answers:
Usimov [2.4K]4 years ago
5 0
The magnesium metal is highly reactive and can ignite in contact with moisture or even air. The skin is usually covering in moisture, so the contact with it may cause a reaction that can produce irritation, lesions and even burns.

Crucible tongs are mandatory to handle hot crucibles to avoid skin burns and accidents during experimental procedures. Crucible tongs work with the crucible; their shape was designed to firmly hold it to avoid spills.

lutik1710 [3]4 years ago
3 0

Touching the magnesium metal can actually contaminate it and bring with it impurities which may not be removed by heating. So this leads to error in weighing.

 

There are two reasons not to touch the crucible tong with bare hands:

1. The crucible tong is used during firing so it is extremely hot and may burn your hands

2. Any impurities in your hand may contaminate the tong hence leading to error just like the case for the magnesium metal

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1. A balloon contains 100g of oxygen gas (O₂) when the volume is 110 dm³. Find the volume of the balloon when the mass of oxygen
igor_vitrenko [27]

The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

We will use the ideal gas equation-

<u>PV=nRT</u>

P=Pressure

V=volume

n=no. of moles

T=temperature

In this question temperature and pressure will remains constant then the above equation can be rewritten as-

V_{1} /n_{1} =V_{2} /n2

where V1= initial volume of the balloon

            V2=  volume of the balloon when the mass of oxygen gas is decreased to 50g

now, substitute the values in the above equation-

  • V1=100dm3=100L
  • n1=100/32=3.12
  • n2=50/32=1.56

       100/3.12=V2/1.56

  • V2=50 L

hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

learn more about the ideal gas equation here:

brainly.com/question/1056445

#SPJ10

3 0
2 years ago
Below are shown, for five metals, reduction reactions and standard electrode potential values. which of these metals is the leas
just olya [345]
Above question is incomplete. Complete question is attached below
........................................................................................................................
Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.

In present case, reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is least reactive.

On other hand, reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is most reactive. 


7 0
4 years ago
A science student makes the following statement I think the color of lights affects the rate of plant growth. Which part of the
ruslelena [56]

Correct, it is a start of a experiment, something that is asked first.


6 0
4 years ago
Read 2 more answers
The average flowrate of hydrochloric acid solution from a plant is 11,900 Lt/hr. The density is the same as that of water (1kg/L
skelet666 [1.2K]

Answer:

See explanation.

Explanation:

Hello,

Here, considering the given flowrate, we perform the following units conversions for each case:

(i)

11,900 \frac{L}{h} *\frac{0.264172 gal}{1L} *\frac{1h}{60min} =52.39\frac{gal}{min}

(ii)

11,900 \frac{L}{h} *\frac{1kg}{1L}*\frac{2.20462lbm}{1kg}=26,234\frac{lbm}{h}

(iii)

11,900 \frac{L}{h} *\frac{0.015gmolHCl}{1L}*\frac{1h}{60min}=2.975\frac{gmolHCl}{min}

(iv) We find the kg of HCl per kg of acid solution:

w_{HCl}=0.015\frac{gmolHCl}{Lsln}*\frac{36.45gHCl}{1gmolHCl} *\frac{1kgHCl}{1000gHCl}*\frac{1Lsln}{1kgsln} =5.4675x10^{-4}

(v)

n_{HCl}=0.015\frac{gmolHCl}{L}*\frac{1000L}{1m^3}  *1m^3=15gmolHCl

Best regards.

8 0
3 years ago
To the nearest whole number how many moles are in 130 g sample of calcium metal?
lesantik [10]
To convert grams to moles, we need the molar mass of the element or compound. remember you can determine the molar mass of a molecule by adding the atomic mass of each atom from the periodic table.

molar mass of Na= 23.0 g/ mol

130 g (1 mol Na/ 23.0 grams)= 5.65 moles or 6 moles.
6 0
4 years ago
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