The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
We will use the ideal gas equation-
<u>PV=nRT</u>
P=Pressure
V=volume
n=no. of moles
T=temperature
In this question temperature and pressure will remains constant then the above equation can be rewritten as-

where V1= initial volume of the balloon
V2= volume of the balloon when the mass of oxygen gas is decreased to 50g
now, substitute the values in the above equation-
100/3.12=V2/1.56
hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.
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Above question is incomplete. Complete question is attached below
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Solution:
Reduction potential of metal ions are provided below. Higher the value to reduction potential, greater is the tendency of metal to remain in reduced state.
In present case,
reduction potential of Au is maximum, hence it is least prone to undergo oxidation. Hence, it is
least reactive.
On other hand,
reduction potential of Na is minimum, hence it is most prone to undergo oxidation. Hence, it is
most reactive.
Correct, it is a start of a experiment, something that is asked first.
Answer:
See explanation.
Explanation:
Hello,
Here, considering the given flowrate, we perform the following units conversions for each case:
(i)

(ii)

(iii)

(iv) We find the kg of HCl per kg of acid solution:

(v)

Best regards.
To convert grams to moles, we need the molar mass of the element or compound. remember you can determine the molar mass of a molecule by adding the atomic mass of each atom from the periodic table.
molar mass of Na= 23.0 g/ mol
130 g (1 mol Na/ 23.0 grams)= 5.65 moles or 6 moles.