What is the percentage composition of cucl

2 answers:

6 0

The formula weight of CuCl is: 98.999

Percent compositions are usually weight percent (abbreviated w/o). 

Since CuCl has one mole of each element, the calculation is simple. 

For Cu it is: (63.546 / 98.999) x 100% = 64.189 w/o 

For Cl it is 100.000 - 64.189 = 35.811 w/o

valentina_108 [34]3 years ago

3 0

Answer:

Cu = 64.189%

Cl = 35.811%

Explanation:

Percentage composition = (mass/molar mass) x 100

CuCl Molar Mass 98.999g/mol

Cu = 63.546g/mol

Cl = 35.453g/mol

Cu = (63.546/98.999) x 100 = 64.189

Cl = (35.453/98.999) x 100 = 35.811

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What would be the final temperature of a 73.174g sample

madreJ [45]

The final temperature is -138 °C.

Explanation:

Using the equation of specific heat

$Q = m*c* del T$

We can easily find the final temperature of a 73.174 g of copper sample. As we know that specific heat is the amount of energy required to raise the temperature of the object to 1°C.

The specific heat of copper is known as 0.387 J/g°C and the initial temperature is said as 102 °C . The mass is given as 73.174 g. The heat released is 6800 J.

Since the heat is released the Q value will be negative.

$-6800=0.387*73.174*(T_{final}-102)$