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3 years ago

What is the percentage composition of cucl

2 answers:

6 0

The formula weight of CuCl is: 98.999

Percent compositions are usually weight percent (abbreviated w/o). 

Since CuCl has one mole of each element, the calculation is simple. 

For Cu it is: (63.546 / 98.999) x 100% = 64.189 w/o 

For Cl it is 100.000 - 64.189 = 35.811 w/o

valentina_108 [34]3 years ago

3 0

Answer:

Cu = 64.189%

Cl = 35.811%

Explanation:

Percentage composition = (mass/molar mass) x 100

CuCl Molar Mass 98.999g/mol

Cu = 63.546g/mol

Cl = 35.453g/mol

Cu = (63.546/98.999) x 100 = 64.189

Cl = (35.453/98.999) x 100 = 35.811

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

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Answer: The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

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Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

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Now, calculating the mass of chromium (III) oxide from equation 1, we get:

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Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

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