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lorasvet [3.4K]
3 years ago
14

What is the percentage composition of cucl

Chemistry
2 answers:
mart [117]3 years ago
6 0
The formula weight of CuCl is: 98.999 

<span>Percent compositions are usually weight percent (abbreviated w/o). </span>

<span>Since CuCl has one mole of each element, the calculation is simple. </span>

<span>For Cu it is: (63.546 / 98.999) x 100% = 64.189 w/o </span>

<span>For Cl it is 100.000 - 64.189 = 35.811 w/o </span>
valentina_108 [34]3 years ago
3 0

Answer:

Cu = 64.189%

Cl = 35.811%

Explanation:

Percentage composition = (mass/molar mass) x 100

CuCl Molar Mass 98.999g/mol

Cu = 63.546g/mol

Cl = 35.453g/mol

Cu = (63.546/98.999) x 100 = 64.189

Cl =  (35.453/98.999) x 100 = 35.811

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Explanation:

It is known that length of a bond is inversely proportional to the bond strength. This also means that a single bond has long length due to which it is weak in nature.

And, a double bond is shorter in length and has more strength as compared to a single bond. Whereas a triple bond has the smallest length and it has high strength as compared to a double or single bond.

For example, carbon monoxide is CO where there is a triple bond between the carbon and oxygen atom.

Carbon dioxide is CO_{2} where there exists a double bond between the carbon and oxygen atom.

A carbonate ion is CO^{2-}_{3} when two oxygen atoms are attached through single bond with the carbon atom and another oxygen atom is attached through a double bond to the carbon atom.

Hence, we can conclude that order of increasing bond strength of the given carbon oxygen bond is as follows.

        Carbonate ion < carbon dioxide < carbon monoxide

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3 years ago
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3 years ago
How do you balance the equation in number one?
AleksAgata [21]
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To balace the eqaution, you need to have the same number of atoms for each element on both the reactant (left) and product (right) side. 

To start off, you wanna know the number of atoms in each element on both sides, so take it apart:

[reactants]        [product]
Na- 1               Na- 2

N- 1               N- 2(it's 2 because the the subscript [2] is outside of the parenthesis)

O- 4              O- 7 (same reason as above) 

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Na is not balanced out, so add a coefficient to make it the same on both sides.In this case, multiply by 2: 

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Now Na is balanced, but the N and O are also effected by this, so they also have to be multiplied by 2 and they become: 

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3 0
3 years ago
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Ede4ka [16]

Answer: 2.12\times 10^{25} atoms of hydrogen are there in

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There are 2.12\times 10^{25} atoms of hydrogen are there in

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