Answer:
5 meters per second squared
Explanation:
We calculate the acceleration using the formula:
a = (vf - vi) / t
where "vf" is the final velocity, "vi" the initial velocity, and "t" the time it took to change from the initial velocity to the final one.
In our case:
a = (45 - 5) / 8 = 40 / 8 = 5 m/s^2
The gravitational force acting between them is 
Data given;
- M1 = 45kg
- M2 = 11kg
- r = 2.0m
- G =

To solve this question, we need to apply gravitational force or energy formula.
<h3>Gravitational Force</h3>
This states that the force of attraction between two bodies is equal to the product of their bodies and inversely proportional to the square of their distance apart.
Mathematically;

let's substitute the values and solve

The force of gravity acting between them is 
Learn more on gravitational force here;
brainly.com/question/11359658
In electrical circuit, this arrangement is called a R-L series circuit. It is a circuit containing elements of an inductor (L) and a resistor (R). Inductance is expressed in units of Henry while resistance is expressed in units of ohms. The relationship between these values is called the impedance, denoted as Z. Its equation is
Z = √(R^2 + L^2)
Z = √((1.24×10^3 ohms)^2 + (6.95×10^-6 H)^2)
Z = 1,240 ohms
The unit for impedance is also ohms. Since the circuit is in series, the voltage across the inductor and the resistor are additive which is equal to 12 V. Knowing the impedance and the voltage, we can determine the maximum current.
I = V/Z=12/1,240 = 9.68 mA
But since we only want to reach 73.6% of its value, I = 9.68*0.736 = 7.12 mA. Then, the equation for R-L circuits is

, where τ = L/R = 6.95×10^-6/1.24×10^3 = 5.6 x 10^-9
Then,
t = 7.45 nanosecondsPart B.) If t = 1.00τ, then t/τ = 1. Therefore,
I = 6.12 mA
Answer:
The base of taller buildings are made broader because it reduces the pressure exerted on the ground so that they do not sink in due to the extremely high pressure of the building.
Explanation:
hope thiss helpss~!
Answer:
P = 0.27R from the center
Explanation:
Given,
The radius of the uniform circular plate, R = 2R
The radius of the hole, r = R
The center of the smaller circle from the center is, d = 0.8R
The center of mass of a circular disc with a hole in it given by the formula
P = dr²/R² - r²
Where P is the distance from the center of mass located in the line joining the two centers opposite to the hole.
Substituting the given values in the above equation,
P = 0.8R x R² / 4R² - R²
= 0.27R³/R²
= 0.27R
Hence the center of mass of plate is at a distant P = 0.27R from the center