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cricket20 [7]
3 years ago
9

How many seconds long is this chemistry class if it last 40.0 minutes

Chemistry
2 answers:
Westkost [7]3 years ago
6 0

Answer:

2,400 seconds

Explanation:

I multiplied the time value by 60 to get my answer

Hope this helped!

ziro4ka [17]3 years ago
4 0
Around 2,400 seconds would be in a 40.0 minute class
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Does the amount of mentos affect the height of the pop explosion
Sergio039 [100]

Answer:

no

Explanation:

bcuz science

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2 years ago
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A civil engineer chooses to use wooden beams because they will sag before
wolverine [178]

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B. choosing a material that will show warning before it fails.

Explanation:

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3 years ago
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If a system performs 147 kJ of work while receiving 47 kJ of heat, what is change in its internal energy?
Verdich [7]

Answer:

-100 kJ

Explanation:

We can solve this problem by applying the first law of thermodynamics, which states that:

\Delta U = Q-W

where:

\Delta U is the change in internal energy of a system

Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)

W is the work done by the system (it is positive if done by the system, negative if done on the system)

For the system in this problem we have:

W = +147 kJ is the work done by the system

Q = +47 kJ is the heat absorbed by the system

So , its change in internal energy is:

\Delta U = +47 - (+147) =-100 kJ

6 0
3 years ago
a block of iron has the dimensions of 3.00 cm x 3.00 cm x 3.00 cm. it has a mass of 213 g. what is its density? a. 638 g/cm3 b.
Juliette [100K]
Volume = 3 cm × 3cm × 3cm
             =  27 cm ³

Mass  =  213 g

Density  =  \frac{MASS}{VOLUME}
 
              = <span>\frac{213 g}{27 cm ^{3} }
</span> 
<span>              =  7.89 g / cm³

Thus answer is D.</span>
8 0
3 years ago
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ΚΕ:<br> m.22<br> 2<br> What is the kinetic energy of 10kg dog running with a velocity of 12m/s?
BigorU [14]

Answer:

The answer is

<h2>720 Joules</h2>

Explanation:

The kinetic energy of a body can be found by using the formula

<h3>K.E =  \frac{1}{2}  {mv}^{2}</h3>

where

m is the mass

v is the velocity / speed

From the question

mass = 10 kg

velocity = 12 m/s

Substitute the values into the above formula and solve

That's

<h3>KE =  \frac{1}{2}  \times 10 \times  {12}^{2}  \\   = 5 \times 144  \:  \:</h3>

We have the final answer as

<h3>720 Joules</h3>

Hope this helps you

3 0
3 years ago
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