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cricket20 [7]
3 years ago
9

How many seconds long is this chemistry class if it last 40.0 minutes

Chemistry
2 answers:
Westkost [7]3 years ago
6 0

Answer:

2,400 seconds

Explanation:

I multiplied the time value by 60 to get my answer

Hope this helped!

ziro4ka [17]3 years ago
4 0
Around 2,400 seconds would be in a 40.0 minute class
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In a room full of air, the air is mainly composed of Nitrogen and Oxygen molecules (both at room temperature). Find (to two sign
zloy xaker [14]

Explanation:

Expression for the v_{rms} speed is as follows.

            v_{rms} = \sqrt{\frac{3kT}{M}}

where,   v_{rms} = root mean square speed

                     k = Boltzmann constant

                    T = temperature

                    M = molecular mass

As the molecular weight of oxygen is 0.031 kg/mol and R = 8.314 J/mol K. Hence, we will calculate the value of v_{rms} as follows.

               v_{rms} = \sqrt{\frac{3kT}{M}}

                            = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.02 K}{0.031 kg/mol}}

                            = 498.5 m/s

Hence, v_{rms} for oxygen atom is 498.5 m/s.

For nitrogen atom, the molecular weight is 0.028 kg/mol. Hence, we will calculate its v_{rms} speed as follows.

                v_{rms} = \sqrt{\frac{3kT}{M}}

                              = \sqrt{\frac{3 \times 8.314 J/mol K \times 309.92 K}{0.028 kg/mol}}

                              = 524.5 m/s

Therefore, v_{rms} speed for nitrogen is 524.5 m/s.

3 0
3 years ago
Consider the balanced chemical equation: 2o3(g) → 3o2(g). how many moles of o2 are produced when 0.50 mol of o3(g) reacts
kiruha [24]
   2O3→3O2
 The  number  of moles of O2  that  are   produced  when 0.50  moles  of O3(g)  reacted is  0.75  moles

  calculation and explanation

   2  moles    of O3(ozone)  react  to give   3 moles of O2  (oxygen  gas,therefore the reacting   ratio  between O3 :O2 is  2:3

 
 if 0.50  moles of  O3  reacted  then,by use  of  reacting ratio (2:3)  find the moles of O2  produced

That is   0.50 x3/2  =  0.75   moles
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