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Lynna [10]
3 years ago
12

The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i

nto two beakers. He dropped an iron nail (Fe(s)) into one beaker. He dropped a silver rod (Ag(s)) into the other. Write the chemical equation of any reactions he saw.
Chemistry
1 answer:
lakkis [162]3 years ago
6 0

Answer:

CuSO4 + Fe -> FeSO4 + Cu

Explanation:

This reaction is a classic example of a redox reaction. I won't go in too deep, but the basic thing is that electrons from the Fe atom go to the Cu2+ ion. Therefore, Fe becomes an ion, and Cu - an electroneutral atom:

Fe + Cu2+ -> Fe2+ + Cu.

Silver is not a very reactive metal and it does not give up its electrons to Cu.

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\boxed{ \text{9.0 mol of ZnCO$_{3}$}}

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\text{Moles of ZnCO$_{3}$} =\text{3.0 mol Zn$_{3}$(PO$_{4})_{2}$ } \times \dfrac{\text{3.0 mol ZnCO$_{3}$}}{\text{1 mol Zn$_{3}$(PO$_{4}$)$_{2}$}} \\\\\\= \text{9.0 mol ZnCO$_{3}$}

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