All categories

3 years ago

Find the value of 7 + 32 (-5 + 1) ÷ 2.

Mathematics

1 answer:

alexandr1967 [171]3 years ago

3 0

Answer: The required value of the given expression is -57.

Step-by-step explanation: We are given to find the value of the following expression :

$E=7+32(-5+1)\div 2~~~~~~~~~~~~~~~~~~~~~~~~~~`(i)$

We will be using the rule of BODMAS to solve the given problem.

From (i), we have

$E\\\\=7+32(-5+1)\div 2\\\\=7+32(-4)\div 2\\\\=7-128\div 2\\\\=7-\dfrac{128}{2}\\\\=7-64\\\\=-57.$

Thus, the required value of the given expression is -57.

You might be interested in

Which choices are real numbers? Check all that apply.

Nonamiya [84]

Answer:

Step-by-step explanation:

Exponents with fractions in them are really just radical notation in a different form. You've probably seen the square root sign.

That can be written as

x^(1/2)

...and when you take an even root of a negative number, there is no real answer. (2 is an even number).

Looking at the answer choices here, we can see that B and D use even roots, so they will give non-real answers.

So, A and C are the answer choices to select.

5 0

4 years ago

Read 2 more answers

the length of one leg of a right triangle is 20ft, and the length of the hypotenuse is 52 ft. What is the length of the other le

Dima020 [189]

A^2 + b^2 = c^2
20^2 = 400
52^2 = 2704
400 + b^2 = 2704
2704 - 400 = 2304
So you need the square root of 2304 which is 48 so the length of the other leg is 48 ft.

8 0

4 years ago

Leon wants to estimate the proportion of the seniors at his high school who like to watch football. He interviews a simple rando

cupoosta [38]

Answer:

Yes, the random conditions are met

Step-by-step explanation:

From the question, np^ = 32 and n(1 − p^) = 18.

Thus, we can say that:Yes, the random condition for finding confidence intervals is met because the values of np^ and n(1 − p^) are greater than 10.

Also, Yes, the random condition for finding confidence intervals is met because the sample size is greater than 30.

Confidence interval approach is valid if;

1) sample is a simple random sample

2) sample size is sufficiently large, which means that it includes at least 10 successes and 10 failures. In general a sample size of 30 is considered sufficient.

These two conditions are met by the sample described in the question.

So, Yes, the random conditions are met.

5 0

3 years ago

A recent survey of 128 high school students indicated the following information about release times from school.

Delicious77 [7]

Answer:

A) Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

B) The group that wants to get out of school earlier can win after all the votes are counted if their true population proportion takes on a value that is higher than the closest true population proportion (for the group that wants to get out of school later)

That is, in the (31%, 39%) and (35%, 43%) obtained in (a), a range of (35.1%, 39%) and (35%, 38.9%) show how possible that the group that wants to get out of school earlier can win after all the votes are counted.

Step-by-step explanation:

The Interval estimate for the proportion is basically an interval of range of values where the true population proportion can be found with a certain level of confidence.

Mathematically,

Interval estimate = (Sample proportion) ± (Margin of error)

Margin of Error is the width of the confidence interval about the proportion.

a) Find the interval estimates

i) for those that want to get out earlier and

ii) those that want to get out later.

i) Sample proportion of those that want to get out earlier = 35%

Margin of Error = 4%

Interval estimate for those that want to get out earlier = (35%) ± (4%) = (31%, 39%)

ii) Sample proportion of those that want to get out later = 39%

Margin of Error = 4%

Interval estimate for those that want to get out later = (39%) ± (4%) = (35%, 43%)

b) Explain how it would be possible for the group that wants to get out of school earlier to win after all the votes are counted.

Since the interval estimates represent the range of values that the true population proportion can take on for each group that prefer a particular option, the group that wants to get out of school earlier van have their proportion take on values between 31% and 39%. If their true population takes on a value that is highest (which is very possible from the interval estimate), and the group with the highest proportion in the sample, (the group that wants to get out of school later, whose true population proportion can take between 35% and 43%) has a true population proportion that is less than that of the group that wants to get out of school earlier, then, the group that wants to get out of school earlier can win after all the votes are counted.

Hope this Helps!!!

3 0

4 years ago

Simplify the following expression

vova2212 [387]

Answer:

A.( 3m+28)/4

Step-by-step explanation:

So basically since it is addition we just add 9 to -2 to get 7. So then the equation becomes (3m/4)+7. Then we will multiply 7 by 4 to get common denominator so it will be (3m+(7*4))/4 which is (3m+28)/4.

7 0

3 years ago