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Paraphin [41]
3 years ago
10

How many significant figures are in the measurement 0.0030010 kilograms?

Chemistry
2 answers:
devlian [24]3 years ago
6 0
There are 5 significant figures
inessss [21]3 years ago
6 0

No, I believe it's 7

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what two bodies of water form a key transportation route connecting the interior of Canada to the Atlantic Ocean? and its scienc
hodyreva [135]

Answer:

Lake Ontario and St Lawrence Seaway

Explanation:

The Great Lakes are connected to the Atlantic Ocean through the St. Lawrence Seaway.

5 0
3 years ago
0.22 L of HNO3 is titrated to equivalence using 0.10 L of 0.1 MNaOH. What is the concentration of the HNO3?
White raven [17]

Answer:- Molarity of the acid solution is 0.045M.

Solution:- The balanced equation for the reaction of given acid and base is:

HNO_3+NaOH\rightarrow NaNO_3+H_2O

From the balanced equation, they react in 1:1 mol ratio. So, we could easily solve the problem using the equation:

M_aV_a=M_bV_b

where, M_a is the molarity of acid, M_b is the molarity of base, V_a is the volume of acid and V_b is the volume of base.

Let's plug in the given values in the equation:

M_a(0.22L)=0.1M(0.10L)

on rearranging the above equation:

M_a=\frac{0.1M(0.10L)}{0.22L}

M_a = 0.045M

So, the molarity of the acid solution is 0.045M.

3 0
3 years ago
Will mark brainliest if correct
Sergeeva-Olga [200]

Answer:

a and d

Explanation:

4 0
2 years ago
A chemist has 2.0 mol of methanol (CH3OH). Molar mass of menthanol is 32.0g/mol. What is the mass, in grams, of the sample
Mademuasel [1]
2.0 mol x 32.0 g / 1 mol =
3 0
3 years ago
vaporized at 100°C and 1 atmosphere pressure. Assuming ideal gas 1 g mole of water is behavior calculate the work done and compa
Vesna [10]

Answer:

q = 40.57 kJ; w = -3.10 kJ; strong H-bonds must be broken.

Explanation:

1. Heat absorbed

q = nΔH = 1 mol × (40.57 kJ/1 mol) = 40.57 kJ

2. Change in volume

V(water) = 0.018 L

pV = nRT

1 atm × V = 1 mol × 0.082 06 L·atm·K⁻¹mol⁻¹ × 373.15 K

V = 30.62 L

ΔV = V(steam) - V(water) = 30.62 L - 0.018 L = 30.60 L

3. Work done

w = -pΔV = - 1 atm × 30.60 L = -30.60 L·atm

w = -30.60 L·atm × (101.325 J/1 L·atm) = -3100 J = -3.10 kJ

4. Why the difference?

Every gas does 3.10 kJ of work when it expands at 100 °C and 1 atm.

The difference is in the heat of vaporization. Water molecules are strongly hydrogen bonded to each other, so it takes a large amount of energy to convert water from the liquid phase to the vapour phase.

7 0
3 years ago
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