Ask question

Ask question

All categories

3 years ago

7

Infer the direction of the net force acting on a car as it slows down and turns right.

2 answers:

Kobotan [32]3 years ago

6 0

Net force would be towards the right and back (opposite direction of motion) since it's slowing down (decelerating) and turning right.

xxTIMURxx [149]3 years ago

3 0

Explanation:

From Newton's second law of motion:

Force acting on a body, <em>F = ma</em>

<em>where, m is the mass and a is the acceleration.</em>

When the car is slowing down, it is actually decelerating. The direction of force is the direction of the acceleration. Since, the car is decelerating, the direction of net force acting would be opposite to the direction of motion of car. And when the car turns right, the net force is also directed towards right.

You might be interested in

A 12.0 kg object is attached to a cord that is wrapped around a wheel of radius 10.0 cm. the acceleration of the object down the

olganol [36]

a) We use the formula:

T = [g sinθ – a] * m

where g is gravity, θ is the angle, a is acceleration, m is mass

T = [9.81 sin37 - 2.00] * 12 = 46.85 N <span>

b) We use the formula for moment of interia:</span>

I = T * r² / a

I = 46.85 * 0.10² / 2.00 = .2343 kg∙m² <span>

c) The formula we can use here is:</span>

w = α * t = (a/r) * t

w = (2/.10) * 2

<span>w = 40 rad/sec</span>

6 0

3 years ago

The temperature on a warm day is 309.7 K. Calculate the equivalent to this temperature on Fahrenheit temperature scale.

Lynna [10]

Answer:

97.79

Explanation:

4 0

3 years ago

Starting from home, you bicycle 25 km north in 2.4 h and then turn around and pedal straight home in 1.4 h . What are your (a) d

AnnZ [28]

Answer:

Part a)

$d = 25 km$

Part b)

$v_{avg} = 10.42 km/h$

Part c)

$v_{avg} = 17.86 km/h$

Part d)

Displacement for entire trip = 0

Part e)

Average velocity for entire trip will be zero

Explanation:

Part a)

Displacement after t = 2.4 hours is the straight line distance between initial and final positions

so we have

$d = 25 km$

Part b)

Average velocity is defined as

$v_{avg} = \frac{displacement}{time}$

$v_{avg} = \frac{25 km}{2.4 h}$

$v_{avg} = 10.42 km/h$

Part c)

During his return journey the displacement will be same

$displacement = 25 km$

$time = 1.4 h$

so average velocity is defined as

$v_{avg} = \frac{25 km}{1.4 h}$

$v_{avg} = 17.86 km/h$

Part d)

Displacement for entire trip = 0

as initial and final position will be same

Part e)

Average velocity for entire trip will be zero

6 0

3 years ago

A gas has a volume of 60dm³ when it is under a pressure of 30kpa. Calculate it's volume when pressure changes

vesna_86 [32]

Explanation:

Given that,

Initial volume = 60dm³

Initial pressure = 30 kPa

We need to find the new volume when pressure changes to 40 kPa (say).

We know that the mathematical relation between volume and pressure is given by :

$\dfrac{P_1}{P_2}=\dfrac{V_2}{V_1}$

Put all the values,

$V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{30\times 60}{40}\\\\V_2=45\ dm^3$

So, when pressure of the gas increases, its volume get decreased.

7 0

3 years ago

All protons in a vacuum have the same<br> 1) Speed<br> 2) Wavelength<br> 3) Energy<br> 4) Frequency

IRISSAK [1]

4). Frequency

I had a class on it.

5 0

3 years ago