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3 years ago

Infer the direction of the net force acting on a car as it slows down and turns right.

2 answers:

6 0

Net force would be towards the right and back (opposite direction of motion) since it's slowing down (decelerating) and turning right.

xxTIMURxx [149]3 years ago

3 0

Explanation:

From Newton's second law of motion:

Force acting on a body, F = ma

where, m is the mass and a is the acceleration.

When the car is slowing down, it is actually decelerating. The direction of force is the direction of the acceleration. Since, the car is decelerating, the direction of net force acting would be opposite to the direction of motion of car. And when the car turns right, the net force is also directed towards right.

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Which one of the following statements concerning the momentum of a system when the net force acting on the system is equal to ze

Alex

Answer:

Explanation:

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3 years ago

A constant torque of 3 Nm is applied to an unloaded motor at rest at time t = 0. The motor reaches a speed of 1,393 rpm in 4 s.

irakobra [83]

Answer:

The moment of inertia of the motor is 0.0823 Newton-meter-square seconds.

Explanation:

From Newton's Laws of Motion and Principle of Motion of D'Alembert, the net torque of a system ( $\tau$ ), measured in Newton-meters, is:

$\tau = I\cdot \alpha$ (1)

Where:

$I$ - Moment of inertia, measured in Newton-meter-square seconds.

$\alpha$ - Angular acceleration, measured in radians per square second.

If motor have an uniform acceleration, then we can calculate acceleration by this formula:

$\alpha = \frac{\omega - \omega_{o}}{t}$ (2)

Where:

$\omega_{o}$ - Initial angular speed, measured in radians per second.

$\omega$ - Final angular speed, measured in radians per second.

$t$ - Time, measured in seconds.

If we know that $\tau = 3\,N\cdot m$ , $\omega_{o} = 0\,\frac{rad}{s }$ , $\omega = 145.875\,\frac{rad}{s}$ and $t = 4\,s$ , then the moment of inertia of the motor is: