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Lynna [10]
4 years ago
14

If a radio wave has a period of 1 μs what is the wave's period in seconds

Physics
1 answer:
Nezavi [6.7K]4 years ago
7 0

Answer:

10^{-6} s


Period of wave is defined by the time taken to complete one cycle of the wave i.e. from one crest to one trough.

Since, the period of the wave is already given in microseconds, we just have to convert into seconds.

we know

1\mu s=10^{-6} s


Therefore, the period of wave would be 10^{-6} s
.




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The temperature of a sample of silver increased by 24.0 °C when 269 J of heat was applied. What is the mass of the sample?
statuscvo [17]

Answer:

Mass of the silver will be equal to 46.70 gram

Explanation:

We have given heat required to raise the temperature of silver by 24°C is 269 J , so \Delta T=24^{\circ}C

Specific heat of silver = 0.240 J/gram°C

We have to find the mass of silver

We know that heat required is given by

Q=mc\Delta T, here m is mass, c is specific heat of silver and \Delta T is rise in temperature

So 269=m\times 0.240\times 24

m = 46.70 gram

So mass of the silver will be equal to 46.70 gram

3 0
3 years ago
What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?
eduard

Answer:

Average power output of athlete = 11025 Watts

Explanation:

Work done is defined as the product of force applied and the displacement perpendicular to the force.

Work = Force\times Displacement

Power is defined as work done per unit time.

Power = \frac{Work done}{Time}

Here the person lifts 900 kg.

Height = 2.5 m

Time interval = 2 seconds

Force = weight \times gravity

          = 900 \times 9.8

          = 8820 N

Work done = Force\times Displacement

                   = 8820 \times 2.5

                   = 22050 J

Power = \frac {22050}{2}

           = 11025 Watt

                 

3 0
3 years ago
A wire must be replaced in a circuit by a new wire of the same material but nine times longer. If the new wire's resistance is t
Blizzard [7]

Answer:

three times the original diameter

Explanation:

From the wire's resistance formula, we can calculate the relation between the diameter of the wire and its length:

R=\rho\frac{l}{\pi \frac{d^2}{4}}\\d=\sqrt{\rho \frac{4 l}{\pi R}}\\

Here, d is the wire's diameter, \rho is the electrical resistivity of the material and R is the resistance of the wire. We have l'=9l

d'=\sqrt{\rho \frac{4 l'}{\pi R}}\\d'=\sqrt{\rho \frac{4 (9l)}{\pi R}}\\d'=3\sqrt{\rho \frac{4 l}{\pi R}}\\d'=3d

7 0
4 years ago
An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0km/hour is blowing southward.
qaws [65]

Answer:

a)  correct answer is C , b) 14º  from the west to the north, c)   v_{1g} = 300.79 km / h

Explanation:

This is a relative speed exercise using the addition of speeds.

1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C

2 and 3) In this case we must compose the speed using the Pythagorean Theorem.

     v_{1a}² = v_{1g}² + v_{ag}²

where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth

in this case let's clear the speed of the airplane with respect to the Earth

  v_{1g} = √(v_{1a}² - v_{ag}²)

 v_{1g} = √ (310² - 75²)

 v_{1g} = 300.79 km / h

we find the direction of the airplane using trigonometry

   sin θ = v_{ag} / v_{1a}

   θ = sin⁻¹ (v_{ag} /v_{1a})

   θ = sin⁻¹ (75/310)

   θ= 14º

the pilot must direct the aircraft at an angle of 14º from the west to the north

7 0
4 years ago
The heaviest invertebrate is the giant squid, which can have a weight of about 1.7 tons spread out over its length of 68 feet. w
DENIUS [597]
In science and engineering, the weight<span> of an object is usually taken to be the force on the object due to gravity. It is calculated by multiplying the mass with the gravitational acceleration.

W = mg = 1700 (9.81) = 16677 N

Hope this answers the question. Have a nice day.</span>
4 0
3 years ago
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