Answer:
(4) 8.5 m/s
Explanation:
You add both the meters together and both the seconds together and then divide them both.
Answer:
1, When Jane brakes, the brakes slow the car wheels turning and the road surface exerts a backwards force on the tires, causing the car to decelerate. The pocket book tends to continue on in a straight line (Newton's first law). If she brakes hard enough that the friction between the book and the car seat is insufficient to decelerate the book as fast as the car is decelerating, the book will slide off the seat, and gravity pulls it to the floor
2.
When the diver uses his / her force to depress the springboard, the springboard pushes him back with equal force
3.Newton's Second Law (F=ma)
4. 5 N
5. 19.5 N
65kg * 0.3 m/s^2
6.0.2 N/s
10kg divided by 2N
7.-Walking then pushing the moving forward
-Dribbling
-Basketball is pushed but bounces back
Explanation:
Answer:
v_f = 10.85 m/s
Explanation:
We will apply the law of conservation of momentum here:
where,
m₁ = mass of roller skater = 47 kg
m₂ = mass of bag = 6 kg
v_1i = initial speed of roller skater = 12 m/s
v_2i = initial speed of the bag = 0 m/s
v_1f = final speed of the roller skater = ?
v_2f = final speed of the bag = ?
Both the bag and the skater will have same speed at the end because kater is carrying the bag:
v_1f = v_2f = v_f
Therefore, the equation will become:
<u>v_f = 10.85 m/s</u>
Answer:
27
Explanation:
It moves 13 meters in the first two seconds, backtracks 9 meters in the next 4 seconds, then moves forward 5 meters in the last 4 seconds. The total distance traveled is ...
13 m + 9 m + 5 m = 27 m
_____
In the first interval, the object moves from 1 m to 14 m away from the position reference, hence a move of 13 meters.
The astronaut would collapse under the increased gravity on Jupiter.
