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Reptile [31]
3 years ago
11

Which is most likely why many scientists reject the cold fusion theory?

Chemistry
2 answers:
mina [271]3 years ago
8 0
The original results have not been replicated consistently and reliably.

Sergio [31]3 years ago
7 0
The original results have not been replicated consistently and reliably. Martin Fleischmann and Stanley Pons were the first scientists to have conducted this but when replicated, gave lacking results.
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1. The mass of 6.45 x 1022 atoms C​
Fed [463]

Answer:

\large \boxed{\text{1.29 g}}

Explanation:

We must convert atoms of C to moles of C and then to grams of C.

1. Convert atoms to moles

\text{Moles of C} = 6.45 \times10^{22}\text{ atoms C} \times \dfrac{\text{1 mol C}}{6.022 \times\ 10^{23} \text{ atoms C}} = \text{0.1071 mol C}

2. Convert moles to grams

\text{Mass of C} = \text{0.1071 mol C} \times \dfrac{\text{12.01 g C}}{\text{1 mol C}} = \text{1.29 g C}\\\text{The mass of C is $\large \boxed{\textbf{1.29 g}}$}

7 0
3 years ago
Change of a gas to a liquid
OLEGan [10]
Equally the same paragraph
4 0
3 years ago
Read 2 more answers
In a synthesis reation you stat with 1.7L of hydrogen how many liters of water will be produced?
Vesna [10]

check the answer in Google.

6 0
3 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 385.mg of oxalic acid H2
Vlada [557]

Answer:

The molarity of the sodium hydroxide solution is 0.0692 M

Explanation:

<u>Step 1: </u>Data given

Mass of H2C2O4 = 385 mg = 0.385 grams

volume = 250 mL = 0.250 L

Volume of NaOH = 123.7 mL = 0.1237 L

Molar mass H2C2O4 = 90.03 g/mol

<u>Step 2</u>: The balanced equation

2NaOH + H2C2O4 → Na2C2O4 + 2H2O

<u>Step 3:</u> Calculate moles H2C2O4

Moles H2C2O4 = mass H2C2O4 / molar mass H2C2O4

Moles H2C2O4 = 0.385 grams / 90.03 g/mol

Moles H2C2O4 = 0.00428 moles

<u>Step 4: </u>Calculate molarity of H2C2O4

Molarity H2C2O4 = moles / volume

Molarity H2C2O4 = 0.00428 moles / 0.250 L

Molarity H2C2O4 = 0.01712 M

<u>Step 5:</u> Calculate molarity of NaOH

2*Ca*Va = n*Cb*Vb

⇒ with Ca = Molarity of H2C2O4 = 0.01712 M

⇒ Va = volume of H2C2O4 = 0.250 L

⇒Cb = molarity of NaOH = TO BE DETERMINED

⇒ Vb = volume of NaOH = 0.1237 L

Cb = (2*0.01712*0.250)/0.1237

Cb = 0.0691 M

The molarity of the sodium hydroxide solution is 0.0692 M

4 0
3 years ago
PLEASE HELP ASAP
V125BC [204]

Answer:

third one

Explanation:

5 0
3 years ago
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