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3 years ago

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An element has six valence electrons available for bonding which group of the periodic table does this element most likely belon

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2 answers:

professor190 [17]3 years ago

8 0

Elements in groups 16 has six valance electrons.

Rzqust [24]3 years ago

6 0

Answer:

16th Group.

Explanation:

If there are six valence electrons available for bonding it means there must be two electrons in s sub shell and four in p subshell. Thus the element cannot be s block element and it cannot be d or f block element as well. The element must belong to p block.

The first group of p block contains one electron in outermost p subshell.

The first group is 13th group of periodic table.

so in this way the element with four electrons in valence p block will belong to 16th group.

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X, Y & Z represents 2, 12 & 17 relatively a. Write the electronic configuration of x, y, and z b. Place the elements in

olasank [31]

The electronic configuration of x, y, and z.

$x=1s^2$

$Y= 1s^22s^22p^63s^2$

$Z= 1s^22s^22p^63s^23p^5$

<h3>What is an electronic configuration?</h3>

Electronic configuration, also called electronic structure, is the arrangement of electrons in energy levels around an atomic nucleus.

a.

$x=1s^2$

$Y= 1s^22s^22p^63s^2$

$Z= 1s^22s^22p^63s^23p^5$

b.

x= Period 1 and group18

Y=Element is in period 3 and Group 2

Z=Element is in period 3 and group 17.

c.

X, Y & Z represents Helium, magnesium, and chlorine.

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3 years ago

What has more mass a golf ball or tennis ball ?

Romashka [77]

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3 years ago

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Why does sodium give up an electron?

lidiya [134]

Sodium (Na) has only one electron in its outer electron shell, as shown in Figure 1. Once again, gaining one electron is more energy efficient than losing seven. As a result, it appears to obtain an electron, resulting in an ion with 17 protons, 17 neutrons, and 18 electrons, and a net negative charge (–1).

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3 years ago

How many coulombs are required to plate a layer of chromium metal 0.28 mm thick on an auto bumper with a total area of 0.40 m2 f

Rufina [12.5K]

Explanation:

The given data is as follows.

Thickness = 0.28 mm = $0.28 \times \frac{1}{10}$ cm = 0.028 cm

Area = 0.40 $m^{2}$ = $0.40 \times 10^{4} cm^{2}$ = 4000 $cm^{2}$

As, it is known that volume = area × thickness

So, Volume = $4000 cm^{2} \times 0.028 cm$

= 112 $cm^{3}$

As density is mass divided by volume. So, mass of chromium will be calculated as follows.

Density = $\frac{mass}{volume}$

7.20 $g/cm^{3}$ = $\frac{mass}{112 cm^{3}}$

mass = 806.4 g

As, mass of 1 mole of chromium is 52 g. So, number of moles in 806.4 g of chromium will be as follows.

No. of moles = $\frac{mass}{molar mass}$

= $\frac{806.4 g}{52 g}$

= 15.50 mol

In chromate ion, ( $CrO^{2-}_{4}$ ) charge on Cr is +6. It means that 6 electrons are needed to reduce $Cr^{+6}$ into Cr.

As, 1 mole of $Cr^{+6}$ ions require 6 moles of electrons. Therefore, moles of electrons for 15.50 mol will be calculated as follows.

6 × 15.50 mol = 93.04 mol

To calculate number of electrons we multiply number of moles by Avogadro's number as follows.

$93.04 mol \times 6.02 \times 10^{23}$

= $560.13 \times 10^{23}$

= $5.6 \times 10^{25}$ electrons

There is magnitude of $6.241 \times 10^{18}$ times the charge on an electron is equal to 1 coulomb.

Hence, number of coulombs will be as follows.

No. of coulombs = $\frac{5.6 \times 10^{25}}{6.241 \times 10^{18}}$

= $0.897 \times 10^{7}$ C

or, = $8.97 \times 10^{6}$ C

Thus, we can conclude that $8.97 \times 10^{6}$ C are required to plate a layer of chromium metal with given data.

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2 years ago