FOR THE FIRST PROBLEM:
Differentiating p^2 + 2q^2 = 1100 with respect to time => 2p(dp/dt) + 4q(dq/dt) = 0
<span>dp/dt = -2q/p(dq/dt) </span>
<span>R = pq </span>
<span>dR/dt = p(dq/dt) + q(dp/dt) = -p²/2q(dp/dt) + q(dp/dt) = (2q² - 1100)/2q * (dp/dt) + q(dp/dt) </span>
<span>A = (2q - 550/q)
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Answer:
first question:
range-22
IQR-13
second question:
range-26
IQR-15.5
I hope this helped bestie!
5 1/4 - 2 2/3
first you find the LCM, so u can make both fractions have a like denominator. I'm thinking the LCM is 12, so:
(5 3/12) - (2 8/12)
= 63/12 - 32/12
=31/12
= 2 and 7/12
5 1/4 - 2 2/3 = 2 7/12
The equation given in the question has to be answered to the nearest tenth. The only thing that one should be careful about is the cross multiplication part. Other than that there is no difficulty in the given problem. Now let us get down to the equation in the question.
15/30 = n/34
30 * n = 15 * 34
30n = 510
n = 510/30
= 51/3
= 17
So the value of the unknown variable "n" comes out to be 17.
