1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Citrus2011 [14]
3 years ago
11

An electric field exerts an electrostatic force of magnitude 1.5 x 10-14 newton on an electron within the field. what is the mag

nitude of the electric field strength at the location of the electron?
a.2.4 x 10-33 n/c
b.1.1 x 10-5 n/c
c.9.4 x 104 n/c
d.1.6 x 1016 n/c
Physics
1 answer:
stira [4]3 years ago
7 0
The electrostatic force on the electron is given by
F=qE
where q is the electron charge and E the intensity of the electric field.

So, in order to find E, we just need to re-arrange the formula and use F=1.5 \cdot 10^{-14} N:
E= \frac{F}{q} = \frac{1.5 \cdot 10^{-14}N}{1.6 \cdot 10^{-19}C}=9.4 \cdot 10^4 N/C

So, the correct answer is C.
You might be interested in
Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr
Illusion [34]

Answer:

F_{sprinter}=110.4N

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

W=F_{total}.d

So

W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N  

7 0
2 years ago
Read 2 more answers
Explain why an egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not. (Be sur
Firlakuza [10]

An egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not due to high momentum and acceleration.

<h3>Why an egg thrown at a concrete wall will break?</h3>

An egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not because the momentum and acceleration increases when the egg is thrown downward due to gravity but when we throw an egg in the vertical direction, they move against gravity so the momentum and acceleration decreases.

So we can conclude that an egg thrown at a concrete wall will break, but an egg thrown at a sheet hanging from the ceiling will not due to high momentum and acceleration.

Learn more about momentum here: brainly.com/question/7538238

#SPJ1

4 0
2 years ago
can you help me create a sketch of two different objects with one that has a greater density than the other?
sergey [27]

I don't know how good you are at sketching ... I'm terrible. 
But you can put the point across in a dramatic way if you
can sketch a bowling ball and a basketball ... you'll need
to clearly identify them with the markings you sketch on
each ball. 

They're the same shape and nearly the same size, but
there's a huge difference in their densities.

6 0
3 years ago
.You have always been impressed by the speed of the elevators in your apartment building. You wonder about the maximum accelerat
AlexFokin [52]

Answer:

5.51 m/s^2

Explanation:

Initial scale reading = 50 kg  

assume the greatest scale reading = 78.09 kg

<u>Determine the maximum acceleration for these elevators</u>

At rest the weight is = 50 kg

Weight ( F ) = mg = 50 * 9.81 = 490.5 N<u> </u>

<u> </u>At the 10th floor weight = 78.09 kg

Weight at 10th floor ( F ) = 78.09 * 9.81 = 766.11 N

F = change in weight

Change in weight( F ) = ma = 766.11 - 490.5 (we will take the mass as the starting mass as that mass is calculated when the body is at rest)

50 * a = 275.61

Hence the maximum acceleration ( a ) = 275.61 / 50 = 5.51 m/s^2

3 0
3 years ago
The small spherical planet called "Glob" has a mass of 7.88×1018 kg and a radius of 6.32×104 m. An astronaut on the surface of G
timama [110]

The orbiting speed of the satellite orbiting around the planet Glob is 60.8m/s.

To find the answer, we need to know about the orbital velocity a satellite.

<h3>What's the expression of orbital velocity of a satellite?</h3>
  • Mathematically, orbital velocity= √(GM/r)
  • G= gravitational constant= 6.67×10^(-11) Nm²/kg², M = mass of sun , r= radius of orbit

<h3>What's the orbital velocity of the satellite in a circular orbit with a radius of 1.45×10⁵ m around the planet Glob of mass 7.88×10¹⁸ kg?</h3>
  • Here, M= 7.88×10¹⁸ kg, r= 1.45×10⁵ m
  • Orbital velocity of the orbiting satellite = √(6.67×10^(-11)×7.88×10¹⁸/1.45×10⁵)

= 60.8m/s

Thus, we can conclude that the speed of the satellite orbiting the planet Glob is 60.8m/s.

Learn more about the orbital velocity here:

brainly.com/question/22247460

#SPJ1

6 0
2 years ago
Other questions:
  • Consider an object moving in the plane whose location at time t seconds is given by the parametric equations: x(t)=5cos(πt) y(t)
    7·1 answer
  • Starting friction is the force caused by tiny bonds forming between two surfaces.
    7·1 answer
  • The coloring of the blue morpho butterfly is protective. As the butterfly flaps its wings, the angle at which light strikes the
    11·1 answer
  • How many significant digits are in the measurement 50.003010
    6·1 answer
  • What are 3 facts about cnidarians?
    8·2 answers
  • A farmer lifts his hay bales into the top loft of his barn by walking his horse forward with a constant velocity of 1 ft/s. Dete
    15·1 answer
  • Draw the Lewis dot Structure for the molecule C2H6​
    14·1 answer
  • 1. What coefficients would balance the following equation?
    8·2 answers
  • A body weighing 250 grams was dropped from a helicopter flying at an altitude of 100 meters. Determine the potential energy of t
    15·1 answer
  • Please help!!!
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!