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GREYUIT [131]
3 years ago
11

What can be said about the spontaneity of this reaction? cdiamond→cgraphite

Chemistry
2 answers:
-Dominant- [34]3 years ago
8 0

The forward reaction of C (diamond) -> C (graphite) is spontaneous at 298 K

<h3>Further explanation </h3>

Gibbs free energy is the maximum possible work given by chemical reactions at constant pressure and temperature. Gibbs free energy can be used to determine the spontaneity of a reaction

If the Gibbs free energy value is <0 (negative) then the chemical reaction occurs spontaneously. If the change in free energy is zero, then the chemical reaction is at equilibrium, if it is> 0, the process is not spontaneous

Free energy of reaction (G) is the sum of its enthalpy (H) plus the product of the temperature and the entropy (S) of the system

Can be formulated: (at any temperature)

 \large{\boxed{\bold{\Delta G=\Delta H-T.\Delta S}}}

or at (25 Celsius / 298 K, 1 atm = standard)

ΔG ° reaction = ΔG ° f (products) - ΔG ° f (reactants)

Under standard conditions:

∆G ° = ∆H ° - T∆S °

The value of °H ° can be calculated from the change in enthalpy of standard formation:

∆H ° (reaction) = ∑H ° (product) - ∑ H ° (reagent)

The value of ΔS ° can be calculated from standard entropy data

∆S ° (reaction) = ∑S ° (product) - ∑ S ° (reagent)

If we look at the standard free Gibbs energy for the transformation from diamond to graphite at 298 K:

∆G ° rxn = -2.90 kJ

then a negative value indicates that reaction

C (diamond) -> C (graphite) occurs spontaneously (forward reaction)

 

<h3>Learn more   </h3>

Delta H solution  

brainly.com/question/10600048  

an exothermic reaction  

brainly.com/question/1831525  

as endothermic or exothermic  

brainly.com/question/11419458  

an exothermic dissolving process  

brainly.com/question/10541336  

anastassius [24]3 years ago
7 0
The gibbs free energy of the reaction of diamond to graphite is equal to -2.90 kJ/mol. The free energy is negative which means that the reaction is spontaneous. Therefore, the forward reaction is favored. Hope this helps. Have a nice day.
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\huge \underbrace \mathfrak \red{Answer}

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